Let us assume that there is a 100g sample of Opal. The masses of each element will be:
29.2g Si
33.3g O
37.5g H2O
Now we divide each constituent's mass by its Mr to get the moles present
Si: (29.2 / 28) = 1.04
O: (33.3 / 16) = 2.08
H2O: (37.5 / 18) = 2.08
Now we divide by the smallest number and obtain:
Si: 1
O: 2
H2O: 2
Thus, the empirical formula of Opal is:
SiO2 . 2H2O
Answer: Potassium perchlorate
Explanation:
Answer:
The answer to your question is letter C.
Explanation:
Reaction
Potassium hydroxide = KOH
Barium chloride = BaCl₂
Potassium chloride = KCl
Barium hydroxide = Ba(OH)₂
KOH + BaCl₂ ⇒ KCl + Ba(OH)₂
Reactant Elements Products
1 K 1
1 Ba 1
2 Cl 1
1 H 2
1 O 2
The reaction is unbalanced
2KOH + BaCl₂ ⇒ 2KCl + Ba(OH)₂
Reactant Elements Products
2 K 2
1 Ba 1
2 Cl 2
2 H 2
2 O 2
Now, the reaction is balanced
Answer:
Your coefficients (the numbers in front of the molecule) will be the following from left to right.
1. <u>1 - 2 - 1 - 2</u>
2. <u>2 - 1 - 2 - 2 - 1</u>
3. <u>2 - 4 - 1</u>
4. <u>2 - 4 - 3</u>
5. <u>2 - 2 - 2 - 1</u>
6. <u>1 - 1 - 1</u>
7. <u>2 - 1 - 2</u>
8. <u>3 - 1 - 2 - 3</u>
9. <u>3 - 1 - 2 - 3</u>
10. <u>2 - 1 - 1 - 1</u>
Explanation:
To balance this equations first count how many times an element is on each side and then see what needs to be changed in order to balance them.