Procedure:
1) Integrate the function, from t =0 to t = 60 minutues to obtain the number of liters pumped out in the entire interval, and
2) Substract the result from the initial content of the tank (1000 liters).
Hands on:
Integral of (6 - 6e^-0.13t) dt ]from t =0 to t = 60 min =
= 6t + 6 e^-0.13t / 0.13 = 6t + 46.1538 e^-0.13t ] from t =0 to t = 60 min =
6*60 + 46.1538 e^(-0.13*60) - 0 - 46.1538 = 360 + 0.01891 - 46.1538 = 313.865 liters
2) 1000 liters - 313.865 liters = 613.135 liters
Answer: 613.135 liters
Xy^16 / 4
I don't really know how to explain it, but this is the answer
HCF of 8 that will go as much as possible to 33
4*8=32 and denominator is 8
33-32=1 which is the numerator
Answer is :
4 1/8
Answer:
52 32- cent stamps and 26 13-cent stamps
Step-by-step explanation:
Let x be the 32-cent stamps and y be the 13-cent stamps then...
x=2y
32x+13y=2002 (note that $20.02 is 2002 cents)
We can solve using substitution (substitute 2y for x)
32(2y)+13y=2002
64y+13y=2002
77y=2002
y=26
x=2(26)
x=52
She bought 52 32-cent stamps and 26 13-cent stamps.
