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3 years ago

Can someone PLEASE HELP!!!!!!!!!!!

Mathematics

1 answer:

Nina [5.8K]3 years ago

8 0

Answer:

second one

Step-by-step explanation:

on the 2 , it is painted by black which means x is equal to or smaller than. 2. ( x<_2). And the line is going to the left side ( negative ). Negative numbers are smaller than whole numbers. Also on the -3, the circle is not painted which means x is bigger than -3.

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A new car costs $8000 at full price. With a sales tax of 5.75%, how much will the car cost in total?

ioda

Answer:

$8460

Step-by-step explanation:

So for this problem we will use the base price of $8000 and add the additional cost of the 5.75% to find the total cost for the car.

So, to find the 5.75%, we simply multiply 8000 by .0575 to get 460.

So 8000 + 460 = 8460.

Thus, the total price of the car would be $8460.

Cheers.

3 0

3 years ago

Read 2 more answers

2. The quality assurance department inspects its production line. The product either fails or passes the inspection. Past experi

Oksana_A [137]

Answer:

(a) $E(X) = 950$

(b) $COV = 0.007255$

Step-by-step explanation:

The given problem can be solved using binomial distribution since the product either fails or passes, the probability of failure or success is fixed and there are n repeated trials.

probability of failure = q = 0.05

probability of success = p = 1 - 0.05 = 0.95

number of trials = n = 1000

(a) What is the expected number of non-defective units?

The expected number of non-defective units is given by

$E(X) = n \times p \\\\E(X) = 1000 \times 0.95 \\\\E(X) = 950$

(b) what is the COV of the number of non-defective units?

The coefficient of variance is given by

$COV = \frac{\sigma}{E(X)}$

Where the standard deviation is given by

$\sigma = \sqrt{n \times p\times q} \\\\\sigma = \sqrt{1000 \times 0.95\times 0.05} \\\\\sigma = 6.892$

So the coefficient of variance is

$COV = \frac{6.892}{950}$

$COV = 0.007255$

(c) What is the probability of having more than 980 non-defective units?

We can use the Normal distribution as an approximation to the Binomial distribution since n is quite large and so is p.

$P(X > 980) = 1 - P(X < 980)\\\\P(X > 980) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\$

We need to consider the continuity correction factor whenever we use continuous probability distribution (Normal distribution) to approximate discrete probability distribution (Binomial distribution).

$P(X > 980) = 1 - P(Z < \frac{979.5 - 950}{6.892} )\\\\P(X > 980) = 1 - P(Z < \frac{29.5}{6.892} )\\\\P(X > 980) = 1 - P(Z < 4.28)\\\\$

The z-score corresponding to 4.28 is 0.99999

$P(X > 980) = 1 - 0.99999\\\\P(X > 980) = 0.00001\\\\$

So it means that it is very unlikely that there will be more than 980 non-defective units.

8 0

4 years ago

The polynomial of degree 5, P ( x ) has leading coefficient a=1, has roots of multiplicity 2 at x = 3 and x = 0 , and a root of

ser-zykov [4K]

Answer:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$ , for $r_{1} = 0$

Step-by-step explanation:

The general form of quintic-order polynomial is:

$p_{5}(t) = a\cdot x^{5} + b\cdot x^{4} + c\cdot x^{3} + d\cdot x^{2} + e \cdot x + f$

According to the statement of the problem, the polynomial has the following roots:

$p_{5} (t) = (x - r_{1})\cdot (x-3)^{2}\cdot x^{2} \cdot (x+1)$

Then, some algebraic handling is done to expand the polynomial:

$p_{5} (t) = (x - r_{1}) \cdot (x^{3}-6\cdot x^{2}+9\cdot x) \cdot (x+1)\\p_{5} (t) = (x - r_{1}) \cdot (x^{4}-5\cdot x^{3} + 3 \cdot x^{2} + 9 \cdot x)$

$p_{5} (t) = x^{5} - (5+r_{1})\cdot x^{4} + (3 + 5\cdot r_{1})\cdot x^{3} +(9-3\cdot r_{1})\cdot x^{2} - 9 \cdot r_{1}\cdot x$

If $r_{1} = 0$ , then:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$

5 0

3 years ago

Solve the systems of equations. y=x + 3 y = -x + 1 x = ??? y = ???

riadik2000 [5.3K]

Answer:

x = -1

Step-by-step explanation:

-1 + 3 = 2

-(-1) + 1 = 2 or 1 + 1 = 2

6 0

3 years ago

If A = 6 B = 9 C = 15 Then what is D equal to?

Semmy [17]

A = 6
B = 9
C = 15
D = ?

From A to B, 6 + 3 = 9
From B to C, 9 + 6 = 15
From C to D, 9 + x = ?

The first time, you added 3, for the second time, you added three to the three you are adding, making it 6. So for x, x = 6 + 3, which = 9

9 + 9 = 18

D = 18 should be your answer

hope this helps

6 0

3 years ago