Answer:
B. H1= b1=0
Step-by-step explanation:
the alternative hypothesis is correct
___________________________
◆ AREA RELATED TO CIRCLES ◆ ___________________________
As shown in the figure ,
Radius of circle = 5 cm
Side of square = 2 × (Radius of inscribed circle)
Side of square = 2 × 5 cm
Side of square = 10 cm = a
___________________________
Now ,
Area of shaded region = (Area of square) - ( Area of inscribed circle )
Area of shaded region =

Area of shaded region =

Area of shaded region = 100 - 78.571
Answer:
1480cm³
Step-by-step explanation:
The Equation for the Volume of a Cylinder is V=Bh, where B is the area of the circle (A= πr²).
We are given all of the things we need, we just have to plug them into the equation.
First let's find B using the radius(r) which is given to be 6.4cm, so B=πr²
B=π(6.4cm)²
Plug that into a calculator to get 128.6796351cm²
Now we can plug that into the original equation, V=Bh.
V=(128.6796351cm²)h
h is also given to be 11.5cm, so lets plug that in.
V=(128.6796351cm²)(11.5cm)
You will get V=1479.815804cm³, but since we are rounding to the nearest cubic centimeter, we would round up to 1480cm³.
A nine can go into a 20 two whole times. After that, there's still
some room left in the 20, but it's only enough room for a 2.
A and d I believe..............