Amount owed at the end of 1 year is 3640
<h3><u>Solution:</u></h3>
Given that yoko borrows $3500.
Rate of interest charged is 4% compounded each year
Need to determine amount owed at the end of 1 year.
In our case
:
Borrowed Amount that is principal P = $3500
Rate of interest r = 4%
Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1
<em><u>Formula for Amount of compounded yearly is as follows:</u></em>

Where "p" is the principal
"r" is the rate of interest
"n" is the number of years
Substituting the values in above formula we get


Hence amount owed at the end of 1 year is 3640
Answer:
C. P(E) = 0.9
Step-by-step explanation:
If E needs to be greater than D, then you have two options. 1.5 and 0.9. Since D is 0.5, I think that the most reasonable answer is 0.9.
[If this is wrong, the you know your answer is B. P(E) = 1.5]
The domain is actually the x value of the function, so we need to find the value of x
suppose the width is x, the length is then 3x+5
the area is 50^2 inches, so x(3x+5)=50 => 3x^2+5x-50=0
Factor this quadratic equation: (x-5)(3x+10)=0 =>x=5 or x=-10/3
width can not be negative, so the width is 5
the domain is x=5
baloon poodle requires 1 and giraffe requires 3 balloons.
i really hope this is the correct answer, sorry if I'm wrong.
if you want/need an explanation you can ask me and I'll explain how i did it