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IceJOKER [234]
3 years ago
8

A local donut shop charged $6.50 for a dozen and provided a coupon in the newspaper for $1.50

Mathematics
1 answer:
marusya05 [52]3 years ago
3 0
The red one y=6.50x-0.75
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5/6 + (-1/2)value of sum
bulgar [2K]

Answer:

it's 1/3

Step-by-step explanation:

5/6+(-1/2)

5/6-1/2

LCM= 6

(5-3)/6

2/6

1/3

8 0
3 years ago
Alguien por favor ayuda es para hoy ¿Cuál es la velocidad a la que debe viajar un
iren2701 [21]

Answer:

Speed of vehicle = 500 km/hour

Step-by-step explanation:

Given that:

Distance travel by vehicle = 6,500 km

Time taken by vehicle = 13 hour  

Find:

Speed of vehicle in kilometer per hour

Computation:

Speed = Distance / Time

Speed of vehicle = Distance travel by vehicle / Time taken by vehicle

Speed of vehicle = 6,500 / 13

Speed of vehicle = 500 kilometer per hour

8 0
3 years ago
POINTS!! I NEED HELP WITH THIS, WILL GIVE BRAINLIEST TO BEST ANSWER
neonofarm [45]

Answer:

Conjecture

Disjunction

Counterexample

Conjunction

Inductive reasoning

Conditional

Step-by-step explanation:

I used Quizlet and I knew most of them.

5 0
3 years ago
Read 2 more answers
In a class of 35 students, 19 take history and
saveliy_v [14]

Answer: 9

Step-by-step explanation:

If 19 students take history, 12 take economics and 5 take both:

19-5 = 14 students that take only history

12-5 = 7 students that take only economics

Therefore total number of students who either history, economics or history and economics: 14 + 7 + 5 = 26

Therefore students who take neither: 35 - 26 = 9

4 0
3 years ago
Suppose that f : [a, b] → [a, b] is continuous. Prove that f has a fixed point. That is, prove that there exists c ∈ [a, b] such
nikklg [1K]

Answer:

Step-by-step explanation:

define the function:

g(x) = f(x) -x

As both f(x) and x are continuous functions, g(x) will also be continuous.

Now, what can we say about g(a) = f(a) -a?

we know that a\leq f(a) \leq b, thus:

a-a\leq f(a)-a \leq b-a\\0 \leq g(a) \leq b-a

thus  g(a) is non-negative.

What about g(b) ? Again we have:

a\leq f(b) \leq b\\a-b \leq f(b) -b \leq  0\\a-b \leq g(b) \leq  0

That means that g(b) is not positive.

Now, we can imagine two cases, either one of g(a) or g(b) is equal to zero, or none of them is. If either of them is equal to zero, we have found a fixed point! In fact, any point c for which g(c)=0 is a fixed point, because:

g(c) = 0 \implies f(c) -c = 0 \implies f(c) = c

Now, if g(a) \neq  0 and g(b) \neq 0, then we have that

g(a) >0 and g(b) < 0. And by Bolzano's theorem we can assert that there must exist a point c between a and b for which g(c)=0. And as we have shown before that point would be a fixed point. This completes the proof.

6 0
3 years ago
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