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svp [43]
3 years ago
8

Which equivalence factor should you use to convert from 3.48 x 1018 atoms of Mg to moles of Mg?

Chemistry
1 answer:
Kryger [21]3 years ago
4 0
The first fact you should know to solve a stoichiometric problem like this one is that, there are 6.02 x 10^23 particles (atoms or molecules) in 1 mole of a substance. 

Now, to know the equivalence factor, it is important to know a technique which cancels like units when they are placed diagonally. Hence, to find the moles Mg from atoms, the equivalence factor must have a numerator with units of moles and a denominator with units of atoms. In this case, atoms would be cancelled, leaving the moles.

3.48 x  10^{18} \ atoms\ ( \frac{1 \ mole}{6.02x 10^{23} \ atoms } ) = 5.8x 10^{-6}
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Answer:

680 g/m is the molar mass for the unknown, non electrolyte, compound.

Explanation:

Let's apply the formula for osmotic pressure

π = Molarity . R . T

T = T° absolute (in K)

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As units of R are  L.atm/mol.K, we have to convert the mmHg to atm

760 mmHg  is 1 atm

28.1 mmHg is (28.1  .1)/760 = 0.0369 atm

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(0.0369 atm / 0.082 mol.K/L.atm . 293K) = M

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This data means the mol of solute in 1L, but we have 100mL so

Molarity . volume = mol

0.0015 mol/L . 0.1L = 1.5x10⁻⁴ mole

The molar mass will be: 0.102g / 1.5x10⁻⁴ m = 680 g/m

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Ver explicacion

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