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Nina [5.8K]
3 years ago
11

A certain substance, X, decomposes. 75 % of X remains after 100 minutes. How much X remains after 200 minutes if the reaction or

der with respect to X is the following order: zero order, first order and second order.
Chemistry
1 answer:
frosja888 [35]3 years ago
8 0
This has nothing to do with a question but if anybody’s looking at this question and you see the link that is pretty much on every single question do not click it it is a bot and it will track your IP STAY SAFE!!!plz
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To find the molecular formula from the empirical formula, one must determine the compounds _____
xxTIMURxx [149]

Answer:

Relative molecular of the compound or infomation like vapour density, volume occupied by a known mass of its vapour at stp, etc

Explanation:

The molecular mass of a compound is twice its vapour density. We can find the molecular formula using the relationship below:

  •    Empirical formula is the simplest formula of a compound. It repeats itself "n" times to become a molecular formula i.e (EF)ₙ = MF...... n is the number of times the empirical formula presents in a mole of the compound.
  • Most times, n is a whole number like 1,2,3,.....
7 0
3 years ago
Increase food supplies in an ecosystem decrease competition because the competing organsims would
irga5000 [103]
The competing organisms would eventually outnumber the competition
6 0
3 years ago
The entropy of a system at 337 K increases by 221.7 J/mol•K. The free energy value is found to be –717.5 kJ/mol. Calculate the c
OlgaM077 [116]

<u>Answer:</u> The change in enthalpy for the given system is -642.8 kJ/mol

<u>Explanation:</u>

To calculate the change in enthalpy for given Gibbs free energy, we use the equation:

\Delta G=\Delta H-T\Delta S

where,

\Delta G = Gibbs free energy = -717.5 kJ/mol = -717500 J/mol    (Conversion factor: 1 kJ = 1000 J)

\Delta H = change in enthalpy = ?

T = temperature = 337 K

\Delta S = change in entropy = 221.7 J/mol.K

Putting values in above equation, we get:

-717500J/mol=\Delta H-(337K\times 221.7J/mol.K)\\\\\Delta H=-642787J/mol=-642.8kJ/mol

Hence, the change in enthalpy for the given system is -642.8 kJ/mol

4 0
4 years ago
Convert 44.8 liters of CO2 into particles of CO2​
jonny [76]

Answer:

1.2044 x 10^24 particles

Explanation:

Assuming this is<u> STP</u>....then this is 2 moles    ( each mole = 22.4 L/mole)

  2 moles = 2 * 6.022 x 10^23  = 1.2044 x 10^24

               

5 0
2 years ago
Give the iupac name
xxTIMURxx [149]
5-chloro-3-methyloctane
7 0
3 years ago
Read 2 more answers
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