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Nana76 [90]
2 years ago
5

What is 33 1/3% as a decimal? NOW!!!

Mathematics
2 answers:
Hitman42 [59]2 years ago
8 0

Answer:

0.33

Step-by-step explanation:

To convert a percentage to decimal, we need to divide the percentage by 100%

First, we write it as an improper fraction. So we get ....

33 1/3 % = 100/3 %

Then to get rid of the percentage sign, we need to divide the number by 100% ...

100/3 ÷ 100 = 100/3 x 1/100 = 1/3

Now that we have gotten rid of the percentage sign, we have the answer in fraction ... we will now convert the fraction to decimal.

1/3 = 0.33 (nearest hundredth)

Anna35 [415]2 years ago
3 0

Answer:

0.333333 repeating

Step-by-step explanation:

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It would be 2:3 and 3:2
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The temperature on Wednesday evening was -°5 Fahrenheit. The temperature decreased another 8° throughout the night. Wjat was the
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The temperature on Thursday morning would be -13°F.

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3 years ago
Find 8 and one third percent of 144
madam [21]
\bf 8\frac{1}{3}\implies \cfrac{8\cdot 3+1}{3}\implies \cfrac{25}{3}
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now\qquad \cfrac{\frac{25}{3}}{100}\implies \cfrac{\frac{25}{3}}{\frac{100}{1}}\implies \cfrac{25}{3}\cdot \cfrac{1}{100}\implies \cfrac{1}{3\cdot 4}\implies \cfrac{1}{12}
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8\frac{1}{3}\%\ of\ 144\implies  \left( \cfrac{\frac{25}{3}}{100} \right)\cdot 144\implies \cfrac{1}{12}\cdot 144\implies \cfrac{144}{12}\implies 12
3 0
2 years ago
Find the standard deviation of the sample ($23.14, $20.12, $56.21, $34.56, $43.74)
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Step-by-step explanation:

6 0
3 years ago
Extension question (provide a full explanation of your method(s):
Volgvan

Answer:

Ann has little chance to win if she is presented with 4 counters.

Ann can always win from a pile of 6 counters.

(both are explained below)

Step-by-step explanation:

If Ann  is presented with 4 counters, and

1. if she takes out 3, she will lose since the opponent will  pull out 1 and the last one.

2. if she takes 2 her opponent will take out 1 and she can't pull out the last 1 since her opponents last move was to pull out 1  counter so she will lose.

3. If she takes out 1 and her opponent takes out 3 in the next move she loses.

but if instead of 3 her opponent takes out 2 and in the last move Ann takes out the last 1  then she will win.

So, If Ann is presented with 4 counters she has little chance to win provided in the move just before, her opponent didn't move 1 counter.

Now,

if there is 6 counters to Ann, and

1., if Ben's  previous move was 1 then Ann can win if she takes out 3 or 2.

If she takes out 3 Ben can take out 1 or 2 and in the last move she will take out 2 or 1 (respectively) and winning the game.

If she takes out 2 Ben can  take out 1 or 3 and in the last move Ann wins by pulling out 3 or 1 respectively.

2. if Ben's  previous move was 2 then Ann can win if she takes out 1 or 3.

If she takes out 1 Ben can take out 2 or 3 and in the last move she will take out 3 or 2(respectively) and winning the game.

If she takes out 3 Ben can  take out 1 or 2 and in the last move Ann wins by pulling out 2 or 1 respectively.

2. if Ben's  previous move was 3 then Ann can win if she takes out 1 or 2.

If she takes out 1 Ben can take out 2 or 3 and in the last move she will take out 3 or 2(respectively) and winning the game.

If she takes out 2 Ben can  take out 1 or 3 and in the last move Ann wins by pulling out 3 or 1 respectively.

 

 

7 0
3 years ago
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