The set $\{x\mid x^4-x^3-x^2-6x+6=0\}$ is the set of all values of $x$ that are solutions to the given equation. So all you need to do is check whether $x=1$ and $x=2$ satisfy the equation.

$x=1\implies 1^4-1^3-1^2-5+6=0$

$x=2\implies2^4-2^3-2^2-10+6=0$

The equation holds, so both 1 and 2 are solutions, and hence $\{1,2\}$ is a subset of the solutions.

6 0

3 years ago

Calculate 7.5cm in km

Ber [7]

0.000075. I asked Siri haha

4 0

3 years ago

Read 2 more answers

If p:q = 1/3:2 and p:r = 1/2:3/4 calculate the ratio p:q:r

kirza4 [7]

Answer:

p:q=1/3:2=1:6=3:18

p:r=3/4:1/2=3:2

p:q:r=3:18:2

i hope its help to you ✌

5 0

2 years ago