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mr Goodwill [35]
3 years ago
8

Convert 5.4 ⋅ 103 to standard form. 0.0054 0.00054 5,400 54,000

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
6 0
54*10 to the 3rd power equals 5'400
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Frank has a jar filled with 200 old dimes. Suppose he selects a dime from the jar without looking. There is a 20% chance that he
a_sh-v [17]

Answer: 40

Step-by-step explanation:

Given

Jar contains 200 old dimes

Chances to pick the 1960s is 20% i.e. 1960s is 20% of 200 old dimes

So, we can write

\Rightarrow \text{No of 1960s is }=20\%\ \text{of}\ 200=0.2\times 200\\\Rightarrow \text{No of 1960s is }=40

8 0
3 years ago
What two numbers add to 8 and multiply to 28
anygoal [31]
Find numbers that multiply to 28 and add them to see if they add to 8
28=
1 and 28=29 not 8
2 and 14=16 not 8
4 and 7=11 not 8
that's it'
no 2 numbers
we must use quadratic formula

x+y=8
xy=28

x+y=8
subtract x fromb oths ides
y=8-x
subsitute
x(8-x)=28
distribute
8x-x^2=28
add x^2 to both sides
8x=28+x^2
subtract 8x
x^2-8x+28=0

if you have
ax^2+bx+c=0 then x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}
so if we have
1x^2-8+28=0 then
a=1
b=-8
c=28

x=\frac{-(-8)+/- \sqrt{(-8)^{2}-4(1)(28)} }{2(1)}
x=\frac{8+/- \sqrt{-48} }{2}
x=\frac{8+/- 4 \sqrt{-3} }{2}
x=4+/- 2 \sqrt{-3}
x=4+/- 2i \sqrt{3}
there are no real numbers that satisfy this
5 0
3 years ago
Five members of the computer club site to buy used computer dividing up the cost equally later three new members join a club of
BartSMP [9]

The computation shows that the price of the used computer is $75.

<h3>How to compute the price?</h3>

From the information given, it should be noted that there are 5 members before the new members joined and $15 was given to each member.

Therefore, the price of the used computer will be:

= $15 × 5

= $75

The price of the used computer is $75.

Learn more about computations on:

brainly.com/question/4658834

#SPJ1

7 0
1 year ago
Don't understand this at all, please help!
stiks02 [169]
For number 4, the midpoint is M, so the lengths of the 2 segments are half of the whole. PM and MQ are 11.

For number 5, TM and MS are 7.5.

Have an amazing day :)
8 0
2 years ago
Consider the functions f(x)=(ax^2-b)/(x^2-4) and g(x)=(x^2-cx+d). if the limit as x approaches 3 equals 6, what is the relations
Dmitry_Shevchenko [17]

6=\dfrac{a\cdot3^2-b}{3^2-4}\\\\&#10;6=\dfrac{9a-b}{5}\\\\\&#10;9a-b=30\\\\&#10;\boxed{b=9a-30}

6 0
3 years ago
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