In the figure below, find x. Assume that segments that appear to be tangent are tangent. Round to the nearest tenth.

Which ordered pair is shown on the graph?

Oliga [24]

Answer:

(2,4)

Step-by-step explanation:

look at the x axis and y axis and see where they meet

6 0

3 years ago

Read 2 more answers

Please, I need help with my homework. I not asking anybody to do it, but I need help for it.

jenyasd209 [6]

Answer:

1) x = -2

Step-by-step explanation:

1) x + 7 + x + 11 = 14

2x + 18 = 14

2x = 14 - 18

2x = -4

x = -4/2 = -2

4 0

3 years ago

Aight ok so if i got two ducks and and i take one how munch is left

vichka [17]

Answer:

1

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

Marcus needs to bike at least 80 miles this week for his training.If he has already biked 25 miles this week ,then how many mile

Orlov [11]

Answer:

11

Step-by-step explanation:

So if he already biked 25 miles we can subtract 80 and 25 which will get a total of 55. if we divided 55 miles to the rest of the 5 days he will have to bike 11 miles each day

5 0

3 years ago

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of te triangle is 16m to the power of 2, what are the base

Olenka [21]

Answer:

The base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

Step-by-step explanation:

Given:

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.

Now, to find the base and height of the triangle.

The base of triangle = $x\times\frac{1}{2} =\frac{x}{2} \ m.$

The height of triangle = $x\times \frac{3}{4} =\frac{3x}{4}\ m.$

The area of triangle = $16\ m^2.$

Now, we put the formula of area to solve:

$Area=\frac{1}{2} \times base\times height$

$16=\frac{1}{2} \times \frac{x}{2} \times \frac{3x}{4}$

$16=\frac{3x^2}{16}$

Multiplying both sides by 16 we get:

$256=3x^2$

Dividing both sides by 3 we get:

$\frac{256}{3} =x^2$

Using square root on both sides we get:

$\frac{16}{\sqrt{3}}=x$

$x=\frac{16}{\sqrt{3}}$

Now, by substituting the value of $x$ to get the base and height:

$Base=\frac{x}{2}\\\\Base=\frac{\frac{16}{\sqrt{3}}}{2} \\\\Base=\frac{8}{\sqrt{3}} \ m.$

So, the base of triangle = $\frac{8}{\sqrt{3}} \ m.$

$Height=x\times\frac{3}{4} \\\\Height=\frac{16}{\sqrt{3}}\times \frac{3}{4} \\\\Height=\frac{12}{\sqrt{3}} \ m.$

Thus, the height of triangle = $\frac{12}{\sqrt{3}} \ m.$

Therefore, the base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

7 0

4 years ago

In the figure below, find x. Assume that segments that appear to be tangent are tangent. Round to the nearest tenth.​

In the figure below, find x. Assume that segments that appear to be tangent are tangent. Round to the nearest tenth.