Given
P(1,-3); P'(-3,1)
Q(3,-2);Q'(-2,3)
R(3,-3);R'(-3,3)
S(2,-4);S'(-4,2)
By observing the relationship between P and P', Q and Q',.... we note that
(x,y)->(y,x) which corresponds to a single reflection about the line y=x.
Alternatively, the same result may be obtained by first reflecting about the x-axis, then a positive (clockwise) rotation of 90 degrees, as follows:
Sx(x,y)->(x,-y) [ reflection about x-axis ]
R90(x,y)->(-y,x) [ positive rotation of 90 degrees ]
combined or composite transformation
R90. Sx (x,y)-> R90(x,-y) -> (y,x)
Similarly similar composite transformation may be obtained by a reflection about the y-axis, followed by a rotation of -90 (or 270) degrees, as follows:
Sy(x,y)->(-x,y)
R270(x,y)->(y,-x)
=>
R270.Sy(x,y)->R270(-x,y)->(y,x)
So in summary, three ways have been presented to make the required transformation, two of which are composite transformations (sequence).
Answer:
$8.40
Step-by-step explanation:
12.00 x .30= 3.60
12.00-3.60=8.40
Answer:
900
Step-by-step explanation:
None of the numbers beginning with 8 are palindromic. There aren't very many numbers that are that are also 5 digits long.
The first digit cannot be 0 (otherwise you will wind up with a 4 digit number)
The first digit can be 9 others.
The second digit can be all 10 digits
The third digit can also be all 10 digits.
The first digit and the 5th digit must be the same so the fifth digit does not add anything new or more palindromic numbers.
The 2nd and 4th must also be the same.
So the total number of palindromic numbers that are 5 digits long
9 * 10 * 10 = 900
There really aren't any more.
80908 is one example of a palindromic 5 digit number.
32 times bc emma skydived 16 times and it says sue sky dived 2 ×
Nico so you would divide 16 ÷ 2 and get 8 then it says gus has skydived 4 times more than nico so you do 8 × 4 and get 32 as your answer
