8x - 6 - 12x^2 + 9x
2(4x-3)-3x(3x-3)
=> (2-3x)(3x-3)
=> 3(x-1)(2-3x)
Answer:
The coordinates of the vertices are;
(200, 200), (300, 200), (300, 0), (0, 500)
Step-by-step explanation:
The vertices are the corners of a polygon. It is the point where an angle is formed by the intersection of two lines
The feasible region is the solution space of the points of the variables that meet the specification of the problem set by means of a constant or the definition of inequalities or equations
From the graph of the function of inequalities, we have that the four vertices are the four points where the lines bounding the area of the feasible region of the inequalities meet
The coordinates of the vertices are (200, 200), (300, 200), (300, 0), (0, 500).
The answer is : impossible
Q1. The answers are (–1, 8), (0, 7), (3, 18)
<span>–3x + y ≥ 7
</span>Let's go through all choices:
<span>(–2, –3)
</span>(-3) * (-2) + (-3) ≥ 7
6 - 3 ≥ 7
3 ≥ 7 INCORRECT
(–1, 8)
(-3) * (-1) + 8 ≥ 7
3 + 8 ≥ 7
11 ≥ 7 CORRECT
(0, 7)
(-3) * 0 + 7 ≥ 7
0 + 7 ≥ 7
7 ≥ 7 CORRECT
(1, 9)
(-3) * 1 + 9 ≥ 7
-3 + 9 ≥ 7
6 ≥ 7 INCORRECT
(3, 18)
(-3) * 3 + 18 ≥ 7
-9 + 18 ≥ 7
9 ≥ 7 CORRECT
Q2. The answers are:
5x + 12y ≤ 80
x ≥ 4
<span>y ≥ 0
</span>
<span>x - small boxes
</span><span>y - large boxes
</span>He has x small boxes that weigh 5 lb each and y large boxes that weigh 12 lb each <span>on a shelf that holds up to 80 lb:
5x + 12y </span>≤ 80
Jude needs at least 4 small boxes on the shelf: x ≥ 4
Let's check if y can be 0:
5x + 12y ≤ 80
5x + 12 * 0 ≤ 80
5x + 0 ≤ 80
5x ≤ 80
x ≤ 80 / 5
x ≤ 16
x ≥ 4 can include x ≤ 16
So, y can be 0: y ≥ 0
Answer:
Step-by-step explanation:
y = (-1/4)x - 4 has a y-intercept of (0, -4). Place a dark dot at (0, -4).
Now we use the info from the slope, -1/4:
Starting with your pencil point on the dot (0, -4), move the pencil point 4 units to the right and then 1 unit down. You will now be at (4, -5). Place a dark dot there.
Then draw a straight, solid line through (0, -4) and (4, -5).
