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tatuchka [14]
3 years ago
15

The ordered pairs in the table below represent a linear function. What’s the slope of the function?

Mathematics
1 answer:
Afina-wow [57]3 years ago
7 0

Answer:

The slope is 2

Step-by-step explanation:

Using slope formula (y2-y1)/(x2-x1):

(8-2)/(9-6)

(6)/3

2

Math Genius
2 years ago
Thank you! :3
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In 2013 Traci joined a swim club. The fees were £600 per year in 2013. Each year the fees increase by 6%. Calculate, to nearest
balandron [24]

Answer:

715 pounds

Step-by-step explanation:

<em>FV = solve</em>

<em>PV = 600</em>

<em>I% = 6</em>

<em>K = 1, N = 3 </em>(2013 - 2016 = 3 years)

Plug it in:

<em>FV = 600 x [ 1 + (6/100 x 1)]³</em>

= 600 x ( 1 + 0.06)³

= 600 x (1.06)³

FV = 714.61, 715 to the nearest dollar.

<em>Therefore, the fee in 2016 is 715 pounds.</em>

6 0
3 years ago
Danielle runs an afterschool program for children. The local baseball team donated 220 game tickets to the program. If Danielle
musickatia [10]
220 / 4 = 55 tickets per unit
7 0
4 years ago
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Is 135 pages in 90 minutes faster that 180 pages in 120 minutes
ElenaW [278]

Answer:

they are the same

Step-by-step explanation:

7 0
3 years ago
Find the vertical and horizontal asymptote if they exist
tresset_1 [31]

Hello!

Vertical asymptotes are determined by setting the denominator of a rational function to zero and then by solving for x.

Horizontal asymptotes are determined by:

1. If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

2. If the degree of the numerator = degree of denominator, then y = leading coefficient of numerator / leading coefficient of denominator is the horizontal asymptote.

3. If degree of numerator > degree of denominator, then there is an oblique asymptote, but no horizontal asymptote.

To find the vertical asymptote:

2x² - 10 = 0

2(x² - 5) = 0

(x - √5)(x + √5) = 0

x = √5 and x = -√5

Graphing the equation, we realize that x = -√5 is not a vertical asymptote, so therefore, the only vertical asymptote is x = √5.

To find the horizontal asymptote:

If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

Therefore, the horizontal asymptote of this function is y = 0.

Short answer: Vertical asymptote: x = √5 and horizontal asymptote: y = 0

7 0
3 years ago
Find the sum and product of the roots of each equation of <img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title=
Neko [114]

Answer:

\huge\boxed{\sf S = 0, P = -16}

Step-by-step explanation:

<u>Given the equation:</u>

\sf x^2 -16 = 0

Comparing it with \sf x^2-Sx+P= 0, where S is the sum and P is the product.

So,

Sum = S = 0

Product = P = -16

Hope this helped!

<h2>~AnonymousHelper1807</h2>

7 0
3 years ago
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