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NeX [460]
2 years ago
9

Please help need someone’s help ASAP

Mathematics
2 answers:
Cloud [144]2 years ago
6 0

The coordinates of Z are (0, -t).

This is because ordered pairs are written in the form (x,y), where the first number represents the number of units the point has moved along the x axis and the second number represents the number of units the point has moved along the y axis. Point Z is on the y axis, which means it has moved 0 units along the x axis (it has an x value of 0). Its y value is -t because it has the same y value as the point directly above it, except it is negative (it moved down instead of up). Therefore, the answer is (0,-t).

Hope this helps!

xxTIMURxx [149]2 years ago
5 0

your answer is D

hope this helps

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antiseptic1488 [7]
A) (0,1), (1,-2), (-1,4), (2,-5)
b) (0,4), (-1,2), (-2,0), (1,6)
c) (-2,-7), (-1, -7), (0,-7), (1, -7)
3 0
2 years ago
Bill’s car gets 30 miles to the gallon. For every gallon of gas it consumes, his car runs 30 miles. Use this information to dete
pshichka [43]

this relation is a function, y=30x

for every ax or 1 gallon, it goes 30 miles.

6 0
3 years ago
X^+5x+8=0<br> What is the answer to this question
ira [324]

Step-by-step explanation:

X^+5x+8=0

x^2+5x=-8 kajvdvdhxjxjjxjxjxjxhx

5 0
3 years ago
Miss lead says that if y varies directly with x and y=15 when x=-3, then y=-20 when x=4. Is she correct? Answer in complete sent
gizmo_the_mogwai [7]

Answer:

Yes,  she is correct.

Step-by-step explanation:

y = kx   is direct variation

15 = k*-3

k = -5.

So the equation of variation is

y = -5x

When x = -4:

y -5*-4 = 20.

6 0
1 year ago
Cna i get some help with dis plz
Tomtit [17]

Let b_1,b_2,\ldots,b_{20} be the 20 marks of the boys, and g_1,g_2,\ldots,g_{10} be the 10 marks of the girls.

We know that the global mean was 70, meaning that

\dfrac{b_1+b_2+\ldots+b_{20}+g_1+g_2+\ldots+g_{10}}{30}=70

Multiplying both sides by 30 we deduce that the sum of the scores of the whole classroom is

b_1+b_2+\ldots+b_{20}+g_1+g_2+\ldots+g_{10}=2100

By the same logic, we work with the marks of the boys alone: we know the average:

\dfrac{b_1+b_2+\ldots+b_{20}}{20}=62

And we deduce the sum of the marks for the boys:

b_1+b_2+\ldots+b_{20}=1240

Which implies that the sum of the marks of the girls is 2100-1240=860

And finally, the mean for the girls alone is

\dfrac{860}{10}=86

6 0
2 years ago
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