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Gala2k [10]
3 years ago
14

After examining a child at his 2-year checkup, the boy's pediatrician said that the z-score for his height relative to other 2-y

ear-olds in the country was 1.59. The pediatrician explains to the parents that the most extreme 5% of cases often require special treatment or attention. a) Does this child fall into that group? b) What do you need to assume about the heights of 2-year-olds to find your answer to part a? a) The child _______into this group because he is___________than_______ standard deviation from the mean.b) Choose al that apply. A. the distribution of heights is skewed B. the heights are independent C. the distribution of heights is symmetric D. the number of heights is very large E. the distribution of heights is unimodal
Mathematics
1 answer:
Anna [14]3 years ago
8 0

Answer:

Step-by-step explanation:

The pediatrician said that the z-score for the boy's height, relative to other 2-year-olds in the country, was 1.59

He explains to the parents of the boy, that the extreme 5% of cases often require special attention.

(A) Does this child fall into that group?

Yes, this child falls into that group. He is among the extreme 5% of cases at the tail of the distribution.

(B) What do you need to assume about the heights of 2-year-olds, in order to find your answer to part (A)?

Assume that the distribution of heights is skewed, the heights are independent of one another, and the number of heights is very large.

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We can let x be the number of boxes sold for the first week. We can as well express the number of boxes for the second and third week through x using the statements provided.

Since the girl scout sold 5 more boxes on the second week, we have (x + 5) number of boxes sold for the second week. Now, for the third week, since it's double that of the second week, we have 2(x + 5). Thus, we have the following:

first week: x
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third week: 2(x + 5)

Given that the total number of boxes sold for the three weeks is 431. We have

x + (x + 5) + 2(x + 5) = 431
x + x + 5 + 2x + 10 = 431
4x + 15 = 431
4x = 431 - 15
4x = 416
x = 104

We have now the value of x. Using this, we can find the values for the second and third week.
x + 5 = `104 + 5 = 109
2(x + 5) = 2(109) = 218

Answer: 
first week: 104
second week: 109
third week: 218



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