The slope (increase) is 0.26 and the y-intercept (start) is 67.6.
You could describe the temperature outside using this equation.
For example, at the beginning of the day, the temperature was 67.6. Then, it increase by 0.26 degree for every given amount of time (minutes or hours).
8-2.5 is 5.5 because when you subtract 2 from 6 you get 6b and when you subtract .5 from 6 you get 5.5
is in quadrant I, so
.
is in quadrant II, so
.
Recall that for any angle
,

Then with the conditions determined above, we get

and

Now recall the compound angle formulas:




as well as the definition of tangent:

Then
1. 
2. 
3. 
4. 
5. 
6. 
7. A bit more work required here. Recall the half-angle identities:



Because
is in quadrant II, we know that
is in quadrant I. Specifically, we know
, so
. In this quadrant, we have
, so

8. 
Answer:
in steps
Step-by-step explanation:
DE // BC
m∠ADE = m∠ABC and m∠AED = m∠ACB
∴ ΔADE similar to ΔABC
AB/AD = AC/AE
(AD + DB) / AD = (AE + EC) / AE
AD/AD + DB/AD = AE/AE + EC/AE
1 + DB/AD = 1 + EC/AE
DB/AD = EC/AE (AD/DB = AE/EC)
Answer:
32 and 27
Step-by-step explanation:
59 - 5 = 54
54 ÷ 2 = 27( smallest no. )
27 + 5 = 32( largest no. )