Is the following relation a function? Give the domain and range

If m 2 n, which inequalities must be true? Check all that apply.

anzhelika [568]

Answer:

$(a)\ m+ 2.1 > n + 2.1$

$(b).\ m - (-4) > n - (-4)$

$(c)\ 9 +m> 6 + n$

Step-by-step explanation:

Given

$m > n$

Required

Select true inequalities

$(a)\ m+ 2.1 > n + 2.1$

Subtract 2.1 from both sides

$m > n$

This is true

$(b).\ m - (-4) > n - (-4)$

Open brackets

$m + 4 > n + 4$

Subtract 4 from both sides

$m > n$

$(c)\ 9 +m> 6 + n$

$m> -9+6 + n$

$m> n-3$

This is also true

8 0

2 years ago

Read 2 more answers

Last month, the daily balance in Joana's credit card account was $1,000 for 9 days, $750 for 10 days, $850 for 4 days, and $900

FrozenT [24]

Answer:

$Average = \$873$

Step-by-step explanation:

Given

$1000 for 9 days

$750 for 10 days

$850 for 4 days

$900 for other days

Required

Compute the daily average

First, we need to compute the number of days her balance is $900

Assuming the billing cycle is 30 days;

$Number\ of\ days = 30 - (9 + 10 + 4)$

$Number\ of\ days = 30 - 23$

$Number\ of\ days = 7$

The Average is then calculates using:

$Average = \frac{\sum fx}{x}$

$Average = \frac{1000 * 9 + 750 * 10 + 850 * 4 + 900 * 7}{9 + 10 + 4+ 7}$

$Average = \frac{26200}{30}$

$Average = 873.333333333$

$Average = \$873$ --- Approximated

3 0

3 years ago

Shakir has relatives in Ottawa, Canada. His aunt told him that the average temperature in April is 8.6°C higher than it is in Ma

34kurt

Answer:

Step-by-step explanation:

did u get the answer?//

3 0

2 years ago

Imogene invested $8,000 in a bank account that pays 8 percent simple interest at the end of each year. Her friend invested the s

Natali5045456 [20]

The right system of equations to describe the situation would be on the form:

x1 = 8000 + y1*t

and

x2 = 8000 + y2*t

where x1 and x2 represents the total money of Imogene and her friend respectively at the end of t years.

Now for the value of amount earned, y1 and y2:

y1=8000*0.08

y2=2000*√(t-2)

5 0

3 years ago

The mean amount spent by a family of four on food per month is $500 with a standard deviation of $75. Assuming that the food cos

JulijaS [17]

Answer:

The probability that a family spends less than $410 per month

P( X < 410) = 0.1151

Step-by-step explanation:

Step(i):-

Given mean of the population = 500

Given standard deviation of the Population = 75

Let 'X' be the variable in normal distribution

$Z = \frac{x-mean}{S.D}$

Given X = $410

$Z = \frac{410-500}{75} = - 1.2$

Step(ii):-

The probability that a family spends less than $410 per month

P( X < 410) = P( Z < - 1.2 )

= 0.5 - A( -1.2)

= 0.5 - A(1.2)

= 0.5 - 0.3849 ( ∵from normal table)

= 0.1151

Final answer:-

The probability that a family spends less than $410 per month

P( X < 410) = 0.1151

6 0

3 years ago