Answer: a force acting between two different molecules
Explanation:
APEX
Answer and Explanation: Ksp is the Solubility Product Constant and is the equilibrium constant that happens when a solid is dissolved in an aqueous solution.
The dissolution of chromium (III) hydroxide:
⇄ 
Every equilibrium constant is of the form:
![K = \frac{[products]^{coefficient}}{[reagents]^{coefficient}}](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B%5Bproducts%5D%5E%7Bcoefficient%7D%7D%7B%5Breagents%5D%5E%7Bcoefficient%7D%7D)
Then,
![K_{sp} = [Cr^{3+}_{(aq)}][OH^{-}_{aq}]^{3}](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BCr%5E%7B3%2B%7D_%7B%28aq%29%7D%5D%5BOH%5E%7B-%7D_%7Baq%7D%5D%5E%7B3%7D)
The reagent is not included because solids don't take part in euqilibrium constants.
<u>So, Ksp of chromium (III) hydroxide is </u>
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Answer:
I think you would use a balance!
Explanation:
The correct number of sig figs for this number is 7 because all whole numbers count and all zeros after the decimal counts too. So, all the numbers count, which is 7.
Answer:
The molar concentration of base Cb = 14.2777M
Explanation:
Volume of acid Va = 38.70cm^3,
Concentration of acid NaO4 C_a= 1.90M
Volume of Base Vb = 10.30cm^3
Also, Equation of the reaction
H2SO4 + 2NaOH = Na2SO4 + 2H2O
No of mole of acid Na = 1
No of mole of base Nb = 2
CaVa/CbVb = Na/Nb
Cb = CaVaNb/VbNa
Cb = 1.9×38.7×2/(10.30×1)
Therefore, Cb = 14.2777M
The molar concentration of base Cb = 14.2777M