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Greeley [361]
3 years ago
9

A tablet of Pain Be Gone Aspirin, which had a mass of 1.213 g, was pulverized and 1.159 g were dissolved in 10.0 mL of ethyl alc

ohol and 25.0 mL of DI water. The titration of this solution with 0.1052 M NaOH required 15.62 mL to reach the phenolphthalein endpoint. Determine the moles of NaOH that reacted with the acetylsalicylic acid.
Chemistry
1 answer:
allochka39001 [22]3 years ago
8 0

Answer:

Moles of NaOH that reacted: n_{NaOH}=1.64*10^{-3}mol

Explanation:

During the  titration, all moles of NaOH added in the solution, react with the acetylsalicylic acid neutralizing each other.

The titration required 15.62 ml (0.01562 L) of the 0.1052 M NaOH solution. The moles of NaOH in that volume are:

n_{NaOH}=0.01562 L * \frac{0.1052mol}{L}

n_{NaOH}=1.64*10^{-3}mol

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