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prohojiy [21]
3 years ago
6

It take 38.70cm³ of 1.90 NaO4 to neutralize 10.30cm³ of H2So4 in a battery. Calculate the molar concentration of H2So4

Chemistry
1 answer:
Anna35 [415]3 years ago
5 0

Answer:

The molar concentration of base Cb = 14.2777M

Explanation:

Volume of acid Va = 38.70cm^3,

Concentration of acid NaO4 C_a= 1.90M

Volume of Base Vb = 10.30cm^3

Also, Equation of the reaction

H2SO4 + 2NaOH = Na2SO4 + 2H2O

No of mole of acid Na = 1

No of mole of base Nb = 2

CaVa/CbVb = Na/Nb

Cb = CaVaNb/VbNa

Cb = 1.9×38.7×2/(10.30×1)

Therefore, Cb = 14.2777M

The molar concentration of base Cb = 14.2777M

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3 years ago
What mass of ammonia can be produced if 13.4 grams of nitrogen gas reacted ?
aivan3 [116]

Answer:

If 13.4 grams of nitrogen gas reacts we'll produce 16.3 grams of ammonia

Explanation:

Step 1: Data given

Mass of nitrogen gas (N2) = 13.4 grams

Molar mass of N2 = 28 g/mol

Molar mass of NH3 = 17.03 g/mol

Step 2: The balanced equation

N2 + 3H2 → 2NH3

Step 3: Calculate moles of N2

Moles N2 = Mass N2 / molar mass N2

Moles N2 = 13.4 grams / 28.00 g/mol

Moles N2 = 0.479 moles

Step 4: Calculate moles of NH3

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

For 0.479 moles N2 we'll produce 2*0.479 = 0.958 moles

Step 5: Calculate mass of NH3

Mass of NH3 = moles NH3 * molar mass NH3

Mass NH3 = 0.958 moles * 17.03 g/mol

Mass NH3 = 16.3 grams

If 13.4 grams of nitrogen gas reacts we'll produce 16.3 grams of ammonia

3 0
3 years ago
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luda_lava [24]
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4 years ago
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I think the answer is option B

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