Answer:
The molar concentration of base Cb = 14.2777M
Explanation:
Volume of acid Va = 38.70cm^3,
Concentration of acid NaO4 C_a= 1.90M
Volume of Base Vb = 10.30cm^3
Also, Equation of the reaction
H2SO4 + 2NaOH = Na2SO4 + 2H2O
No of mole of acid Na = 1
No of mole of base Nb = 2
CaVa/CbVb = Na/Nb
Cb = CaVaNb/VbNa
Cb = 1.9×38.7×2/(10.30×1)
Therefore, Cb = 14.2777M
The molar concentration of base Cb = 14.2777M
