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3 years ago

7

A vertical plane intersects the three-dimensional object in the image and divides the object into equal halves. What is the shap

e of the cross section?
Thank you :)

2 answers:

Crank3 years ago

7 0

If you were to take a knife and cut this shape down the middle, starting from the top, what will the cross section look like?
It will look a lot like how the object looks from the side.
The best answer is D, the last image.

dlinn [17]3 years ago

6 0

Answer:

Option 4 is correct .

Step-by-step explanation:

Given : A three dimensional figure

To Find : What is the shape of the cross section?

Solution :

If we intersects the three-dimensional object in the image and divides the object into equal halves by vertical plane then we can see the attached figure what the output will be .

We can see that if we see the cross section from the side then it looks like the fourth one

So, Option 4 is correct .

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Listed below are prices in dollars for one night at different hotels in a certain region. Find the range, variance, and standar

hodyreva [135]

Answer:

Step-by-step explanation:

Given is a list of prices in dollars for one night at different hotels in a certain region

To find range, variance and std deviation.

Mean 155.75

Standard Error 23.80782434

Median 150

Mode #N/A

Standard Deviation 67.33869616

Sample Variance 4534.5

Kurtosis -1.593759971

Skewness 0.344624422

Range 172

Minimum 86

Maximum 258

Sum 1246

Count 8

Thus we find range = 172 $. This gives an idea about the lowest and highest difference.

Variance = Average of squares of deviations from the mean= 4533.329 $^2gives us an idea about the dispersion of data. This helps to have an idea about the price rise or low in different hotels

Std deviation is square root of variance 67.33 $ shows an idea about the dispersion and also coefficient of variation as a ratio of mean to std deviation.

6 0

4 years ago

What is -4-2? Help please

Natalija [7]

$\bold{Hey\ there!} \\ \bold{-4-2\downarrow}\\ \bold{-4+(-2)}\\ \\ \\ \\ \bullet \bold{negative\ and\ negative = positive} \\ \bullet{\bold{positive\ and\ negative=negative}} \\ \bullet\bold{negative\ and\ positive=negative}\\ \bullet\bold{positive\ and\ positive= positive} \\ \\ \\ \boxed{\bold{This\ means\ that\ your\ answer\ will\ turn\ out\ to\ be\ a\ negative!}} \\ \\ \\ \\ \boxed{\boxed{\bold{Answer:-6(Option\ A.)\checkmark}}}$

$\bold{Good\ luck\ on\ your\ assignment\ and\ enjoy\ day!} \\ \\ \\ \frak{LoveYourselfFirst:)}$

3 0

4 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=5%20%5Ctimes%20%5Cfrac%7B4%7D%7B7%7D%20" id="TexFormula1" title="5 \times \frac{4}{7} " alt="5

Butoxors [25]

$\bf 5\times \cfrac{4}{7}\implies \cfrac{5\cdot 4}{7}\implies \cfrac{20}{7}\implies \cfrac{14+6}{7}\implies \cfrac{14}{7}+\cfrac{6}{7}\implies 2+\cfrac{6}{7}\implies 2\frac{6}{7}$

4 0

3 years ago

Read 2 more answers

Let C(n, k) = the number of k-membered subsets of an n-membered set. Find (a) C(6, k) for k = 0,1,2,...,6 (b) C(7, k) for k = 0,

vladimir1956 [14]

Answer:

(a) $C(6,0) = 1$ , $C(6,1) = 6$ , $C(6,2) = 15$ , $C(6,3) = 20$ , $C(6,4) = 15$ , $C(6,5) = 6$ , $C(6,6) = 1$ .

(b) $C(7,0) = 1$ , $C(7,1) = 7$ , $C(7,2) = 21$ , $C(7,3) = 35$ , $C(7,4) = 35$ , $C(7,5) = 21$ , $C(7,6) = 7$ , $C(7,7)=1$ .

Step-by-step explanation:

In this exercise we only need to recall the formula for C(n,k):

$C(n,k) = \frac{n!}{k!(n-k)!}$

where the symbol $n!$ is the factorial and means

$n! = 1\cdot 2\cdot 3\cdot 4\cdtos (n-1)\cdot n$ .

By convention 0!=1. The most important property of the factorial is $n!=(n-1)!\cdot n$ , for example 3!=1*2*3=6.

(a) The explanations to the solutions is just the calculations.

$C(6,0) = \frac{6!}{0!(6-0)!} = \frac{6!}{6!} = 1$

$C(6,1) = \frac{6!}{1!(6-1)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6$

$C(6,2) = \frac{6!}{2!(6-2)!} = \frac{6!}{2\cdot 4!} = \frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15$

$C(6,3) = \frac{6!}{3!(6-3)!} = \frac{6!}{3!\cdot 3!} = \frac{5!\cdot 6}{6\cdot 6} = \frac{5!}{6} = \frac{120}{6} = 20$

$C(6,4) = \frac{6!}{4!(6-4)!} = \frac{6!}{4!\cdot 2!} = frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15$

$C(6,5) = \frac{6!}{5!(6-5)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6$

$C(6,6) = \frac{6!}{6!(6-6)!} = \frac{6!}{6!} = 1$ .

(b) The explanations to the solutions is just the calculations.

$C(7,0) = \frac{7!}{0!(7-0)!} = \frac{7!}{7!} = 1$

$C(7,1) = \frac{7!}{1!(7-1)!} = \frac{7!}{6!} = \frac{6!\cdot 7}{6!} = 7$

$C(7,2) = \frac{7!}{2!(7-2)!} = \frac{7!}{2\cdot 5!} = \frac{6!\cdot 7}{2\cdot 5!} = \frac{5!\cdot 6\cdot 7}{2\cdot 5!} = \frac{6\cdot 7}{2} = 21$

$C(7,3) = \frac{7!}{3!(7-3)!} = \frac{7!}{3!\cdot 4!} = \frac{6!\cdot 7}{6\cdot 4!} = \frac{5!\cdot 6\cdot 7}{6\cdot 4!} = \frac{120\cdot 7}{24} = 35$

$C(7,4) = \frac{7!}{4!(7-4)!} = \frac{6!\cdot 7}{4!\cdot 3!} = frac{5!\cdot 6\cdot 7}{4!\cdot 6} = \frac{120\cdot 7}{24} = 35$

$C(7,5) = \frac{7!}{5!(7-2)!} = \frac{7!}{5!\cdot 2!} = 21$

$C(7,6) = \frac{7!}{6!(7-6)!} = \frac{7!}{6!} = \frac{6!\cdot 7}{6!} = 7$

$C(7,7) = \frac{7!}{7!(7-7)!} = \frac{7!}{7!} = 1$

For all the calculations just recall that 4! =24 and 5!=120.

6 0

3 years ago

In Texas, 30% of parolees from prison return to prison within 3 years. Suppose 15 prisoners are released from a Texas prison on

LUCKY_DIMON [66]

Answer:

N = 15 ; P = 0.3

Step-by-step explanation:

According to the question, the data provided in the question is as follows

The percentage of parolees from prison return to prison = 30%

Number of years = 3 years

Number of prisoners released from a Texas prision is 15

Based on the above information, the value of the parameters for the binomial random variable X is

N = 15 = number of prisoners

And, the P = Percentage = 30% = 0.3

4 0

3 years ago