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oksano4ka [1.4K]
4 years ago
14

Is this statement is true -8< 8

Mathematics
1 answer:
prohojiy [21]4 years ago
6 0
Yes 8>-8 because 8 is negative
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Estimate the square root of - 27 to the nearest tenth.
Aleonysh [2.5K]

Answer:

C (5.2)

Step-by-step explanation:

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3 years ago
(a + b - c )(a + b + c )
denis-greek [22]

Answer:

a^2+b^2-c^2+2ab

Step-by-step explanation:

(a+b-c)(a+b+c)=a^2+ab+ac+ab+b^2+bc-ac-bc-c^2=a^2+b^2-c^2+2ab

Hope this helps!

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3 years ago
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4 years ago
Help with math homework. I'll mark you as brainiest!
lorasvet [3.4K]
For the living room one, you have an 11' wall, & a 2' 6" shelf.
First, we'll divide the length of both in half:
5' 6" wall, 1' 3" shelf
Now, subtract the two:
4' 3"
That's how far away the edge of the shelf needs to be from either corner of the wall to be centered.

For the second one:
We need to get all these numbers into the same formatting. I say we go fraction.
First guy got 13 out of 18
Second guy got .7 (repeating)
Third guy got 5/6
Ok, first, we'll turn .7 repeating into a fraction. This won't always work, because not all decimals will turn into a nice fraction. But this one will.
.7 (repeating) = 7/9
So we have:
13/18
7/9
5/6
Now, we can't compare these quite yet. They all need to have the same denominator. So, what's the LCM of the three denominators? 18, right?
The first one can be left alone, since it has a denominator of 18 already. The second one: multiply both numbers by 2, and we get 14/18. For the third: multiply everything by 3, and we get 15/18.
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Jon: 13/18
Jim: 14/18
Joe: 15/18
It's now clear that Joe got the highest score.
5 0
4 years ago
UNA POBLACION DE CIERTA CIUDAD EN EL AÑO 2000 ERA DE 250,000 HABITANTES CON UNA TASA DE CRECIMIENTO RELATIVO DEL 2% , DETERMINA
Fofino [41]

Answer:

La población que se espera para el 2012, es 317,060

Step-by-step explanation:

Si la población tiene un crecimiento relativo del 2%, entonces cada año, la población es un 2% más grande que el año anterior.

Definamos P(t) = población después de t años

Entonces, si al año t = 0 (que corresponde con el año 2000) la población es A

P(0) = A

Un año después, en t = 1, la población incrementa en un 2%

P(1) = A + (2%/100%)*A = A + (0.02)*A = A*(1.02)

Otro año después, en t = 2, la población incrementa un 2% de vuelta.

P(2) = A*(1.02) + (2%/100%)*A(1.02) = A*(1.02) + 0.02*A*(1.02)

      = A*(1.02)*(1.02) = A*(1.02)^2

Ya podemos notar un patrón, la población en el año t va a ser:

P(t) = A*(1.02)^t

Sabemos que en t = 0 (el año 2000) la población es 250,000

Entonces A = 250,000

P(t) = 250,000*(1.02)^t

Ahora queremos calcular la población en el año 2012

entonces si t = 0 es el 2000

2012 esta representado con t = 12

Reemplazando eso en la ecuación, obtenemos:

P(12) = 250,000*(1.02)^12 = 317,060.4

Como esto es una población tenemos que redondearlo al próximo número entero, como el primer digito después del punto es 4, redondeamos para abajo.

Entonces la población que se espera para el 2012 es: 317,060

5 0
3 years ago
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