Answer:
180’ - 130’
Step-by-step explanation:
Answer:
<em>4</em><em>*</em><em>5x-7</em><em>=</em><em>20</em>
4*5(-7)-7=20
20(-7)-7=20
-140-7=20
-140=20+7
-140=27
=27+140
<u>=</u><u>167</u>
<em>-</em><em>3x</em><em>+</em><em>7</em><em>=</em><em>28</em>
-3(6)+7=28
-3(6)=28-7
-18=21
=21+18
<u>=</u><u>39</u>
<em>2x</em><em>+</em><em>3</em><em>=-7</em>
2(-5)+3=-7
2(-5)=-7-3
-10=-10
=-10+10
<u>=</u><u>0</u>
Answer:
x = -2
y= -5
is the solution of the system of equations
Answer:
144π
Step-by-step explanation:
radius = 12 cm
area of the circle = π* r² = π * 12² = 144π
For the answer to the question above,
1. If we let x as the side of the square cut-out, the formula for the capacity (volume) of the food dish is:
V = (12 - 2x)(8 - 2x)(x)
V = 96x - 40x^2 + 4x^3
To find the zeros, we equate the equation to 0, so, the values of x that would result to zero would be:
x = 0, 6, 4
2. To get the value of x to obtain the maximum capacity, we differentiate the equation, equate it to zero, and solve for x.
dV/dx = 96 - 80x + 12x^2 = 0
x = 5.10, 1.57
The value of x that would give the maximum capacity is x = 1.57
3. If the volume of the box is 12, then the value of x can be solved using:
12 = 96x - 40x^2 + 4x^3
x = 0.13, 6.22, 3.65
The permissible value of x is 0.13 and 3.65
4. Increasing the cutout of the box increases the volume until its dimension reaches 1.57. After that, the value of the volume decreases it reaches 4.
5. V = (q -2x) (p - 2x) (x)
