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prohojiy [21]
3 years ago
5

If

x} +36=0" align="absmiddle" class="latex-formula">, what is the value of x?
A. 6

B. 6^{2}

C. 6^{3}

D. 6^{4}
Mathematics
1 answer:
Elis [28]3 years ago
6 0

Answer:

x = 36

Step-by-step explanation:

x - 12\sqrt{x} + 36 = 0

Subtract x and 36 from both sides.

-12\sqrt{x} = -x - 36

Divide both sides by -1.

12\sqrt{x} = x + 36

Square both sides.

144x = x^2 + 72x + 1296

Subtract 144x from both sides.

0 = x^2 - 72x + 1296

Factor the right side.

0 = (x - 36)^2

x - 36 = 0

x = 36

Since the solution of the equation involved squaring both sides, we musty check the answer for possible extraneous solutions.

Check x = 36:

x - 12\sqrt{x} + 36 = 0

36 - 12\sqrt{36} + 36 = 0

36 - 12\times 6 + 36 = 0

36 - 72 + 36 = 0

0 = 0

Since 0 = 0 is a true statement, the solution x = 36 is a valid solution.

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