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IrinaK [193]
3 years ago
15

A bag contains equal numbers of green and blue marbles. You can divide all the green marbles into groups of 12 and all the blue

marbles into groups of 16. What is the least number of each color of marble that can be in that bags?
Mathematics
1 answer:
KIM [24]3 years ago
5 0

To solve this problem, we need to find for the LCM of each number. That is:

12: 12, 24, 36, 48, 60

16: 16, 32, 48, 64, 80

 

So we can see that the LCM is 48.

<span>Therefore the least number of each color of marble must be 48.</span>

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Four friends went bowling one afternoon. Use the table that shows the bowling data
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Step-by-step explanation:

By the given table,

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6 0
3 years ago
Solve for x.<br> −7≥13−5x
Sergio039 [100]

Answer:

\[=>x\geq 4\]

Step-by-step explanation:

Given inequality is \[−7\geq13−5x\]

Simplifying:

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\[=>x\geq \frac{20}{5}\]

\[=>x\geq 4\]

Hence the solution for the given inequality is represented by  \[=>x\geq 4\]

This means that the original inequality will be true only for those values of x which are greater than or equal to 4.

4 0
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81.5%
i honestly looked at the numbers in the problem
6 0
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Please help me please
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Answer:

its no big deal

Step-by-step explanation:

no big deal.

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