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IrinaK [193]
3 years ago
15

A bag contains equal numbers of green and blue marbles. You can divide all the green marbles into groups of 12 and all the blue

marbles into groups of 16. What is the least number of each color of marble that can be in that bags?
Mathematics
1 answer:
KIM [24]3 years ago
5 0

To solve this problem, we need to find for the LCM of each number. That is:

12: 12, 24, 36, 48, 60

16: 16, 32, 48, 64, 80

 

So we can see that the LCM is 48.

<span>Therefore the least number of each color of marble must be 48.</span>

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Answer:

$84.75 over budget

Step-by-step explanation:

Barts' budget is 285.75

Bills: 240 + 130.50 = $370.50

(subract by his budget)

370.5 - 285.75 = $84.74

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4 0
3 years ago
Write the first five terms of the sequence in which the nth term is a_n=(n+1)!/n+1.
VikaD [51]

Answer:a) 1,2,6,24,120

Step-by-step explanation:

The formula for the nth term of the sequence is expressed as

n=(n+1)!/n+1

For the first term, n = 1. Therefore,

(1+1)!/(1+1) = 2!/2 = (2×1)/2 = 1

For the second tern, n = 2. Therefore,

(2+1)!/2+1 = 3! /3 = (3×2×1)/3 = 6/3 = 2

For the third term, n = 3, therefore

(3+1)!/3+1 = 4!/4 =(4×3×2×1)/4 = 6

For the fourth term, n = 4. Therefore

(4+1)!/4+1 = 5!/5 = (5×4×3×2×1)/5 = 24

For the fifth term, n = 5. Therefore

(5+1)!/5+1 = 6!/6 = 6× 5×4×3×2×1)/6 = 120

4 0
3 years ago
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OlgaM077 [116]
Yep! You did it correct :)
6 0
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Sonya made a graph showing the first ten minutes of her drive to the movies.
Agata [3.3K]

Answer:

A

Step-by-step explanation:

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Step-by-step explanation:

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