The winter group provides tax advice

ivolga24 [154]

The next larger tenth is 10.1 .
The next smaller tenth is 10.0 .

10.04 is nearer to 10.0 than it is to 10.1 .

So the nearest tenth is 10.0 .

5 0

2 years ago

Oscar draws two lines on his paper. The lines are always one inch apart and do not intersect. Which term can be used to name wha

kaheart [24]

Answer:

Parralel lines

7 0

2 years ago

What is the likelihood that a fair coin will land heads or tails?

Marina CMI [18]

Answer:

I believe it is 0.5

Step-by-step explanation:

If you flip a normal coin (called a “fair” coin in probability parlance), you normally have no way to predict whether it will come up heads or tails. Both outcomes are equally likely. There is one bit of uncertainty; the probability of a head, written p(h), is 0.5 and the probability of a tail (p(t)) is 0.5. The sum of the probabilities of all the possible outcomes adds up to 1.0, the number of bits of uncertainty we had about the outcome before the flip. Since exactly one of the four outcomes has to happen, the sum of the probabilities for the four possibilities has to be 1.0. To relate this to information theory, this is like saying there is one bit of uncertainty about which of the four outcomes will happen before each pair of coin flips. And since each combination is equally likely, the probability of each outcome is 1/4 = 0.25. Assuming the coin is fair (has the same probability of heads and tails), the chance of guessing correctly is 50%, so you'd expect half the guesses to be correct and half to be wrong. So, if we ask the subject to guess heads or tails for each of 100 coin flips, we'd expect about 50 of the guesses to be correct. Suppose a new subject walks into the lab and manages to guess heads or tails correctly for 60 out of 100 tosses. Evidence of precognition, or perhaps the subject's possessing a telekinetic power which causes the coin to land with the guessed face up? Well,…no. In all likelihood, we've observed nothing more than good luck. The probability of 60 correct guesses out of 100 is about 2.8%, which means that if we do a large number of experiments flipping 100 coins, about every 35 experiments we can expect a score of 60 or better, purely due to chance.

6 0

3 years ago

Read 2 more answers

A survey of 500 high school students was taken to determine their favorite chocolate candy. Of the 500 students surveyed, 150 li

Anika [276]

Answer:

N(AUC∩B') = 121

The number of students that like Reese's Peanut Butter Cups or Snickers, but not Twix is 121

Step-by-step explanation:

Let A represent snickers, B represent Twix and C represent Reese's Peanut Butter Cups.

Given;

N(A) = 150

N(B) = 204

N(C) = 206

N(A∩B) = 75

N(A∩C) = 100

N(B∩C) = 98

N(A∩B∩C) = 38

N(Total) = 500

How many students like Reese's Peanut Butter Cups or Snickers, but not Twix;

N(AUC∩B')

This can be derived by first finding;

N(AUC) = N(A) + N(C) - N(A∩C)

N(AUC) = 150+206-100 = 256

Also,

N(A∩B U B∩C) = N(A∩B) + N(B∩C) - N(A∩B∩C) = 75 + 98 - 38 = 135

N(AUC∩B') = N(AUC) - N(A∩B U B∩C) = 256-135 = 121

N(AUC∩B') = 121

The number of students that like Reese's Peanut Butter Cups or Snickers, but not Twix is 121

See attached venn diagram for clarity.

The number of students that like Reese's Peanut Butter Cups or Snickers, but not Twix is the shaded part

6 0

3 years ago

Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

so

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0

2 years ago