The 3-digit number is 132
<h3>How to determine the
3-digit number?</h3>
The given parameters are:
- Number of digits = 3
- Sum of digits = 6
- No 0s in the number
- No repeated digit
The first highlight above implies that the number can be any of 100 to 999
The other highlights imply that the no digit can appear repeatedly, the highest digit in the number is 3, and the number must end with 2.
So, we have:
X32
The first digit is the smallest.
1 is smaller than 3 and 2.
So, we have
132
Hence, the 3-digit number is 132
Read more about digits and numbers at:
brainly.com/question/26856218
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Answer:
Expected value is 4,000
Step-by-step explanation:
To find expected value ⇒ multiply the value by it's probability
40% × ( -25,000 ) = - 10,000
Breaking means neither add nor subtract a given amount
20% × 0 = 0
35% × 40,000 = 14,000
∴ Expected value = -10,000 + 14,000 = 4,000
LOSS: -10,000
BREAK EVEN: 0
WIN: 14,000
Expected value is 4,000
<em>hope this helps....</em>
This formula means that a(n) for n, when n is the term number, will give you the term. Meaning, we just have to plug in 55 for n.
a(55) = -1 + 3(55 - 1)
a(55) = -1 + 3 * 54
a(55) = -1 + 162
a(55) = 161
Answer:
5(3u+2)(8u+3)
Step-by-step explanation:
lmk if you want an explanation