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devlian [24]
3 years ago
7

Please help me with this.

Mathematics
1 answer:
ipn [44]3 years ago
8 0

-5yards+-8yards=-13yards

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Tell me the answer of these question.
Nonamiya [84]
16. \ \ V= \pi r^2h \ \to \ r^2= \cfrac{V}{ \pi h}  \ \to \ \boxed{r= \sqrt{ \frac{V}{ \pi h} } } \\ \\ \\ 17.\ \ d= \frac{1}{2} at^2 \ \to \ 2d= at^2   \ \to \ t^2= \cfrac{2d}{a} \   \to \ \boxed{t= \sqrt{\frac{2d}{a}}} \\  \\   \\ 18. \ \ S=180(n-2) \ \to \  \cfrac{S}{180}=n-2 \ \to \ \boxed{n= \frac{S}{180}+2 }
6 0
3 years ago
Rectangle OPEN has diagonals intersecting at S. If m∠ENP=42 find m∠ EON, m∠ONP, m∠OSP, and m∠PSE
poizon [28]

Answer:

m∠EON = 48°

m∠ONP = 48°

m∠PSE = 90°

4 0
2 years ago
Assume that y varies inversely with x. If y=1/3 when x=1/2, find y when x=1/4.
LenKa [72]

Answer:

y = \frac{2}{3}

Step-by-step explanation:

Given that y varies inversely with x then the equation relating them is

y = \frac{k}{x} ← k is the constant of variation

To find k use the condition y = \frac{1}{3} when x = \frac{1}{2} , thus

\frac{1}{3} = \frac{k}{\frac{1}{2} } = 2k ( divide both sides by 2 )

k = \frac{1}{6}

y = \frac{1}{6x} ← equation of variation

When x = \frac{1}{4} , then

y = \frac{1}{6(\frac{1}{4}) } = \frac{1}{\frac{3}{2} } = \frac{2}{3}

3 0
3 years ago
What are the roots of the equation 5x^2=-9x-6n simplest a+bi form?
iVinArrow [24]
5 square root of 2 is 25.
-9-6 is -15
4 0
3 years ago
50-10x=20 what is the value of x in this problem
Andrew [12]
So what I did was I wrote down the problem 50 - 10x = 20.

The first step I did was take 50 and subtract it from both sides: 50 - 10x = 20
                                                                                                   -50            -50
After that i cross out the so 50's and take 20 and subtract it to 50 which gave me -30. So when you write this down you rewrite it as: -10x = -30

Last step: take the -10 and divide it by both sides the cross out the two -10's cause it's going to be written as -30/-10 which would give you x = 3. So there is your answer, hope this helps. :)

~Shadow


7 0
3 years ago
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