Need help from anyone please even if it's just suggestions on what i could do please i really need help...... The average test s
cores for a particular test in algebra 2 had a mean of 84 with a standard deviation of 5. What percentage of the students scored higher than 89%? Please explain your answer
Study this example to see if it helps. <span>The scores on a certain math test were normally distributed with a mean score of 80 and a standard deviation of 5. What percent of the students scored between 80 and 90?</span>
If the mean (μ) is 80, and the standard deviation (σ) is 5, then all scores between 80 and 90 would fall between 0 and 2 standard deviations above the mean. Using the equation for Z score (Z = (X-μ)/σ) for each X value (80 and 90) then the Z scores are 0 and 2, respectively. Using a normal distribution table, it can be found that P(80 < z) = .5 (this is the probability that a random score would be greater than 80. It makes sense that it is .5 or 50% because 80 is the mean.)And the P(90 > z) = .97725. (this is the probability that a random score would be less than 90.) So the final answers would be (90 > z)-P(80<z) = .47725 or 47.725%
