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Stella [2.4K]
3 years ago
12

How to subtract a negative fraction from a positive fraction?

Mathematics
1 answer:
ikadub [295]3 years ago
8 0
Let's take an example to illustrate this case:

<span>positive fraction = 2/7
</span>
<span>negative fraction = - 3/5

Now we need to subtract  </span><span>- 3/5 from 2/7

Right?

2/7 - (-3/5) = 2/7 + 3/5

here we need to unify the denominators as follows:

the lowest common factor between 7 and 5 is 35
2/7 = 10/35
3/5 = 21/35

Now back to </span><span>2/7 + 3/5:

</span><span><span>2/7 + 3/5 = 10/35 + 21/35 = (10+21)/35 = 31/35

That's it




Hope that helps you</span>
</span>
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densk [106]

Answer:

6

Step-by-step explanation:

3/4 = 6/8.

6/8 divided by 1/8 = 6

brianliest pls

4 0
3 years ago
Any help with this greatly appreciated.
Anestetic [448]

Put the equation in standard linear form.

x'(t) + \dfrac{x(t)}{t + 5} = 5e^{5t}

Find the integrating factor.

\mu = \exp\left(\displaystyle \int \frac{dt}{t+5}\right) = e^{\ln|t+5|} = t+5

Multiply both sides by \mu.

(t+5) x'(t) + x(t) = 5(t+5)e^{5t}

Now the left side the derivative of a product,

\bigg((t+5) x(t)\bigg)' = 5(t+5)e^{5t}

Integrate both sides.

(t+5) x(t) = \displaystyle 5 \int (t+5) e^{5t} \, dt

On the right side, integrate by parts.

(t+5) x(t) = \dfrac15 (5t+24) e^{5t} + C

Solve for x(t).

\boxed{x(t) = \dfrac{5t+24}{5t+25} e^{5t} + \dfrac C{t+5}}

3 0
2 years ago
PYTHAGORAS THEROM AND TRIGONOMETRY RATIO​
marysya [2.9K]

Answer:

1) ΔACD is a right triangle at C

=> sin 32° = AC/15

⇔ AC = sin 32°.15 ≈ 7.9 (cm)

2) ΔABC is a right triangle at C, using Pythagoras theorem, we have:

AB² = AC² + BC²

⇔ AB² = 7.9² + 9.7² = 156.5

⇒ AB = 12.5 (cm)

3)  ΔABC is a right triangle at C

=> sin ∠BAC = BC/AB

⇔ sin ∠BAC = 9.7/12.5 = 0.776

⇒ ∠BAC ≈ 50.9°

4) ΔACD is a right triangle at C

=> cos 32° = CD/15

⇔ CD = cos32°.15

⇒ CD ≈ 12.72 (cm)

Step-by-step explanation:

7 0
3 years ago
Math help me please n
BARSIC [14]

Answer:

Step-by-step explanation:

21x1/12=1.75 cm

1.75x10=17.55 mm

17.55 mm

4 0
3 years ago
(1 point) A rock is thrown into a still pond and causes a circular ripple. If the radius of the ripple is increasing at a rate o
PtichkaEL [24]

Answer:

8pi feet per second

Or, 25.1 feet per second (3 sf)

Step-by-step explanation:

C = 2pi×r

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dC/dt = 25.1327412287

8 0
3 years ago
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