This is incorrect because 2 + 5.8 = 7.8. And 7.8 does not equal 6. 2 + 4 = 6 is the correct answer. This could be represented by this:
2 + x = 6.
Subtract two from both sides to get:
x = 4.
When substituted back into the equation:
2 + (4) = 6.
Answer: -2/5
Step-by-step explanation:
To find the slope, we set the function use y = mx + b forms.
2x + 5y = 10
5y = -2x + 10 Minus 2x in both side
y = -2/5x + 10/5 Divide 5 from both side
y = -2/5x + 2
In the y = mx + b, the m before variable x is always the slope, so -2/5 is the slope for 2x + 5y = 10.
1183 rounded to the nearest hundred = 1200
1145 rounded to the nearest hundred = 1100
Answer:
A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and the number of laps on the vertical axis. 1 lap was 82 to 84 seconds. 4 laps were 84 to 86 seconds. 2 laps were 86 to 88 seconds. 4 laps were 88 to 90 seconds. 6 laps were 90 to 92 seconds. 5 laps were 92 to 94 seconds. 2 laps were 94 to 96 seconds. 0 laps were 96 to 98 seconds
Step-by-step explanation:
The given table is presented as follows;
The number of laps in the range 82 to 84 seconds = 1
The number of laps in the range 84 to 86 seconds = 4
The number of laps in the range 86 to 88 seconds = 2
The number of laps in the range 88 to 90 seconds = 4
The number of laps in the range 90 to 92 seconds = 6
The number of laps in the range 92 to 94 seconds = 5
The number of laps in the range 94 to 96 seconds = 2
The number of laps in the range 96 to 98 seconds = 0
Therefore, the histogram that represents Blanca's lap times for the three days of practice is described as follows;
A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and the number of laps on the vertical axis. 1 lap was 82 to 84 seconds. 4 laps were 84 to 86 seconds. 2 laps were 86 to 88 seconds. 4 laps were 88 to 90 seconds. 6 laps were 90 to 92 seconds. 5 laps were 92 to 94 seconds. 2 laps were 94 to 96 seconds. 0 laps were 96 to 98 seconds
Answer: the future value is $1748.4
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = 1550
r = 4% = 4/100 = 0.04
n = 365 because it was compounded 365 times in a year.
t = 3 years
Therefore,.
A = 1550(1 + 0.04/365)^365 × 3
A = 1550(1+0.00011)^1095
A = 1550(1.00011)^1095
A = 1550 × 1.128
A = 1748.4