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2 years ago

1-8n-6n>1 Solve by simplying into shorter equation

Mathematics

2 answers:

kenny6666 [7]2 years ago

7 0

-14n>0 i think so it would be just n>0

coldgirl [10]2 years ago

6 0

I'm not 100% sure, but I am almost certain that you add your like terms on the left side. This will give you -14n+1>1. Next you want to solve like any other equation. subtract the 1 to the other side, -14n>2. Now, divide by -14. Since you are dividing, you want to flip the sign, so it says n<-1/2. That should be it. I really hope you get this right, and if you don't I'm sorry. It's been a while since I've done this kind of math.

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3 years ago

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3 years ago

Which represents where f(x) = g(x)? A) f(4) = g(4) and f(0) = g(0) B) f(–4) = g(–4) and f(0) = g(0) C) f(–4) = g(–2) and f(4) =

saul85 [17]

Answer:

B. f(-4) = g(-4), and f(0) = g(0)

Step-by-step explanation:

We are given two functions that have been graphed already. The points on the coordinate plane where the curve of g(x) intercepts that of f(x), are the values of x for each function, that would give us the same output (y).

Thus, for f(x) intercepts g(x) at the point where x = -4, y = 4.

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Therefore, the correct answer is f(-4) = g(-4), and f(0) = g(0)

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3 years ago

Given ΔKLM with lengths as marked, what is the relationship of segment NO to segment KL?

Oliga [24]

Segment NO is parallel to the segment KL.

Solution:

Given KLM is a triangle.

MN = NK and MO = OL

It clearly shows that NO is the mid-segment of ΔKLM.

By mid-segment theorem,

<em>The segment connecting two points of the triangle is parallel to the third side and is half of that side.</em>

⇒ NO || KL and $NO = \frac{1}{2}KL$

Therefore segment NO is parallel to the segment KL.

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3 years ago