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vagabundo [1.1K]
3 years ago
13

Liz is shipping a package to her friend.the maximum weight of a medium flat-rate box is 20 pounds,including the box which weighs

6 ounces.write and solve an inequality to describe the possible weight ,w, of the contents that Liz will ship to her friend if she must use a medium flat-rate box.
Mathematics
1 answer:
Murrr4er [49]3 years ago
8 0

Answer:

w+0.375\leq 20 and Liz can ship maximum 19.6 pounds.

Step-by-step explanation:

Let the possible weight of the medium flat-rate box = w pounds.

It is given that there is a box weighing 6 ounces i.e. 0.375 pounds.

Plus, the maximum weight of the package is 20 pounds.

So, we get,

The inequality representing the situation is,

Weight of medium box + 0.375 pounds ≤ Maximum weight of the package

i.e. w+0.375\leq 20

i.e. w\leq 20-0.375

i.e. w\leq 19.6

Thus, Liz can ship maximum 19.6 pounds.

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Alex

Answer:

12(6+9m)

therefore we multiple the 12 by the numbers in the blaket

72+10m

that's the correct answer

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3 years ago
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The u.s. senate consists of 100 members, 2 from each state. A committee of five senators is formed. What is probability it conta
shtirl [24]

Answer:

The probability is 9.80%.

Step-by-step explanation:

The u.s. senate consists of 100 members, 2 from each state.

A committee of five senators is formed.

P(at least one from Your state) = 1- \frac{98c5}{100c5}

= 1- \frac{67910864}{75287520}

= 1-0.9020

= 0.098

That is, 9.80%.

4 0
3 years ago
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8 0
3 years ago
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[Grade 7 set 1]
Veseljchak [2.6K]

Step-by-step explanation:

No it would because you have to find the number for why and the two is the power so no it not going to be.

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3 years ago
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A roll of steel is manufactured on a processing line. The anticipated number of defects in a 10-foot segment of this roll is two
Vikentia [17]

Answer:

the probability of no defects in 10 feet of steel = 0.1353

Step-by-step explanation:

GIven that:

A roll of steel is manufactured on a processing line. The anticipated number of defects in a 10-foot segment of this roll is two.

Let consider β to be the average value for defecting

So;

β = 2

Assuming Y to be the random variable which signifies the anticipated number of defects in a 10-foot segment of this roll.

Thus, y follows a poisson distribution as number of defect is infinite with the average value of β = 2

i.e

Y \sim P( \beta = 2)

the probability mass function can be represented as follows:

\mathtt{P(y) = \dfrac{e^{- \beta} \ \beta^ \ y}{y!}}

where;

y =  0,1,2,3 ...

Hence,  the probability of no defects in 10 feet of steel

y = 0

\mathtt{P(y =0) = \dfrac{e^{- 2} \ 2^ \ 0}{0!}}

\mathtt{P(y =0) = \dfrac{0.1353  \times 1}{1}}

P(y =0) = 0.1353

4 0
3 years ago
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