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Colt1911 [192]
3 years ago
5

What are the first three multiples on 4 , 5 and 10

Mathematics
2 answers:
blondinia [14]3 years ago
5 0

Answer:

4={4,8,12}

5={5,10,15}

10={10,20,30}

Naddik [55]3 years ago
4 0

Answer:

4: 1,2,4

5:1,5

10:1,2,5,10

Step-by-step explanation:

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Find the range of the function. Use interval notation. g(x)=log↓3(x-2)​
Marizza181 [45]

Answer:

10x=log6-3

Step-by-step explanation:

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2 years ago
Which data set has a median of 15? 9, 17, 13, 15, 16, 8, 12 18, 15, 11, 14, 19, 15, 6 7, 16, 14, 16, 11, 7, 17 18, 9, 19, 16, 6,
ivanzaharov [21]

Answer:

The middle number of the data set or average of the two middle numbers in even numbered sets.

Step-by-step explanation:

A median is the middle point of a data set. We order the numbers from least to greatest and find the number directly in the middle of the list. If there are an even number in the set, then we take an average of the middle two.

The data sets are not separated. However, in the sets you have order them least to greatest each. Then count in from both sides to the middle. That number is the middle.

8 0
4 years ago
Please show your work, I'd really appreciate the help! :)
xenn [34]
Y=12.5+1.25X , this is how youget the fair admission amount 43.75-(25x1.25)=12.5
3 0
3 years ago
What is 0.5,3/16,0.75,5/48 from least to greatest
frez [133]
3/16 as a decimal is 0.18
and 5/48 as a decimal is 0.10
SO 
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3 0
3 years ago
The local swim team is considering offering a new semi-private class aimed at entry-level swimmers, but needs a minimum number o
SCORPION-xisa [38]

Answer:

The significance level is \alpha=0.01 and since we are conducting a right tailed test we need to find a critical value who accumulate 0.01 of the area in the right of the normal standard distribution and we got:

z_{\alpha/2}= 2.326

So we reject the null hypothesis is z>2.326

Step-by-step explanation:

For this case we define the random variable X as the number of entry-level swimmers and we are interested about the true population mean for this variable . On specific we want to test this:

Null hypothesis: \mu \leq 15

Alternative hypothesis: \mu > 15

And the statistic is given by:

z =\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

The significance level is \alpha=0.01 and since we are conducting a right tailed test we need to find a critical value who accumulate 0.01 of the area in the right of the normal standard distribution and we got:

z_{\alpha/2}= 2.326

So we reject the null hypothesis is z>2.326

7 0
3 years ago
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