-0,6 i believe would be the same distance from 0,0 as 0,6.
The equation of a hyperbola is:
(x – h)^2 / a^2 - (y – k)^2 / b^2 = 1
So what we have to do is to look for the values of the variables:
<span>For the given hyperbola : center (h, k) = (0, 0)
a = 3(distance from center to vertices)
a^2 = 9</span>
<span>
c = 7 (distance from center to vertices; given from the foci)
c^2 = 49</span>
<span>By the hypotenuse formula:
c^2 = a^2 + b^2
b^2 = c^2 - a^2 </span>
<span>b^2 = 49 – 9</span>
<span>b^2 = 40
</span>
Therefore the equation of the hyperbola is:
<span>(x^2 / 9) – (y^2 / 40) = 1</span>
Answer:
2/(3x-2)²
Step-by-step explanation:
4x²-6x³-2x²+6x³/4x²-6x³-6x³+9x^4=
2x²/4x²-12x³+9x^4=
2x²/x²(4-12x+9x²)=
2/9x²-12x+4
2/(3x-2)²
A = 1.5
B = -1/3
C = -4/3
A is a positive so there is only one possibility
B is in between 0 and -1, so it has to be -1/3
C is below -1 and so its the improper fraction
