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Julli [10]
3 years ago
5

What is the area of this figure?

Mathematics
1 answer:
Leya [2.2K]3 years ago
4 0
A = (3*16) + 1/2(16 + 5)(10)
A = 48 + 105
A = 153 in^2
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Please help with this question ​
svetlana [45]

Answer:The answer to this question would be "1470"To find the volume, all you need to do is Multiply the length, width, and height of the object together and you can find the Volume.Hope this helps, Please mark as Brainliest.

Step-by-step explanation:have a good day.

6 0
3 years ago
Read 2 more answers
An angle in a triangle measures 138 °. The other two angles are congruent. Enter and solve an equation to find the x measure of
Juli2301 [7.4K]

Hey there! I"m happy to help!

The interior angles of a triangle add up to 180. We have 2 angles that have a value of x, so 2x+138=180.

We subtract 138 from both sides.

2x=42

We divide both sides by 2

x=21.

Have a wonderful day! :D

5 0
4 years ago
Find the missing lengths:<br> LO=5 and OK=4, find OH and KH.
hodyreva [135]

Answer:

The length of KH is 6 units and OH is 6.3 units.

Step-by-step explanation:

Given the figure with lengths LO=5 and OK=4. we have to find the length of  OH and KH.

In ΔLOH

By Pythagoras theorem

LH^2=LO^2+OH^2\\\\LH^2=5^2+OH^2 → (1)

In ΔKOH,

KH^2=OH^2+OK^2\\\\KH^2=OH^2+4^2  → (2)

In ΔKHL,

KL^2=LH^2+KH^2

Using eq (1) and (2), we get

KL^2=5^2+OH^2+OH^2+4^2

9^2=25+2OH^2+16

⇒ 2OH^2=81-25-16=40

⇒ OH=\sqrt{20}=6.324\sim6.3units.

Put the above value in eq 2, we get

KH^2=20+4^2=36

⇒ KH=6 units.

8 0
4 years ago
Read 2 more answers
F(x) = x^2 is stretched vertically by a factor of 4 and shifted 1 unit down.<br><br> equation = ???
LenKa [72]

Answer:

f(x) = 4x² - 1

Step-by-step explanation:

The given function is; f(x) = x²

Now, when stretched vertically by a factor of 4, we have;

f(x) = 4x²

It's now shifted 1 unit down.. Thus, the final function will be;

f(x) = 4x² - 1

6 0
3 years ago
Pls solve part b) iii thanks
Viktor [21]

The bearing of the tree from Q is 296.565°

<h3>How to determine the height of the tree?</h3>

The figure that illustrates the bearing and the distance is added as an attachment

The given parameters are:

Base of the tree, b = 50 meters

Angle (x) = 32 degrees

Calculate the height (h) of the tree using:

tan(x) = height/base

So, we have:

tan(32°) = h/50

Make h the subject

h= 50 × tan(32°)

Evaluate

h = 31.24

Hence, the height of the tree is 31.24 meters

<h3>How to determine the distance between Q and the base of the tree?</h3>

The distance (d) between Q and the base of the tree

This is calculated using the following Pythagoras theorem

d = √(100² + 50²)

Evaluate

d = 111.80

Hence, the distance between Q and the base of the tree is 111.80 meters

<h3>How to determine the angle of elevation?</h3>

The angle of elevation (x) using the following tangent trigonometric ratio

tan(x) = h/d

This gives

tan(x) = 31.24/111.80

Evaluate the quotient

tan(x) = 0.2794

Take the arc tan of both sides

x = 15.61

<h3>The bearing of the tree from Q </h3>

This is calculated using:

Angle of bearing = 270 + arctan(50/100)

Evaluate the arc tan

Angle of bearing = 270 + 26.565

Evaluate the sum

Angle of bearing = 296.565

Hence, the bearing of the tree from Q is 296.565 degrees

Read more about bearings at:

brainly.com/question/24142612

#SPJ1

4 0
2 years ago
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