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Korvikt [17]
3 years ago
9

How do you slove this equation 1/5 (k-3)=3/4

Mathematics
1 answer:
vlabodo [156]3 years ago
5 0
The equation is \frac{1}{5}(k-3)= \frac{3}{4}, we want to find the value of k.


Our aim is to isolate k, so we remove the numbers by dividing, subtracting etc.


Firs multiply both sides by 5, to "get rid" of 1/5:

\frac{1}{5}(k-3)= \frac{3}{4} \\\\ 5\cdot \frac{1}{5}(k-3)= 5\cdot\frac{3}{4} \\\\k-3= \frac{15}{4}


now add 3 to both sides:

k-3+3= \frac{15}{4}+3\\\\k=\frac{15}{4}+\frac{12}{4}\\\\k= \frac{27}{4}


Answer: 27/4
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Given:

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m \angle C D A=9 x+3 and m \angle E D A=6 x+5

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What kind of figure and the value of x

Solution:

All four sides are congruent.

Diagonals bisect each other.

There the given figure is rhombus.

Diagonals bisect the angles.

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9 x+3-3=6x+5-3

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Subtract 6x from both sides.

9 x-6x=6x+2-6x

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The value of x is \frac{2}{3}.

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