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Masteriza [31]
2 years ago
14

List the chemicals and apparatus

Physics
1 answer:
Softa [21]2 years ago
4 0

Answer:

Beaker

Graduated Cylinders

Volumetric flask

Test tube

Funnel

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projectile motion of a particle of mass M with charge Q is projected with an initial speed V in a driection opposite to a unifor
SIZIF [17.4K]

Answer:

Range, R = MV²/2QE

Explanation:

The question deals with the projectile motion of a particle mass M with charge Q, having an initial speed V in a direction opposite to that of a uniform electric field.

Since we are dealing with projectile motion in an electric field, the unknown variable here, would be the range, R of the projectile. We note that the electric field opposes the motion of the particle thereby reducing its kinetic energy. The particle stops when it loses  all its kinetic energy due to the work done on it in opposing its motion by the electric field. From work-kinetic energy principles, work done on charge by electric field = loss in kinetic energy of mass.

So, [tex]QER = MV²/2{/tex} where R is the distance (range) the mass moves before it stops

Therefore {tex}R = MV²/2QE{/tex}

5 0
4 years ago
The experimentation step of scientific inquiry involves _______. A. Analyzing data b. Drawing a conclusion c. Choosing variables
Anna11 [10]

Answer:

C- Choosing variables and controls

Explanation:

Correct on edge.

3 0
2 years ago
A red blood cell contains 4.8 107 free electrons. What is the total charge of these electrons in the red blood cell?
tatuchka [14]

Answer:

Charge, q=7.68\times 10^{-12}\ C

Explanation:

It is given that,

The number of electron in a RBCs, n=4.8\times 10^7

We need to find the total charge of these electrons in the red blood cell. Let it is q. Using the quantization of charge as follows :

q = ne

e is the change on electron

q=4.8\times 10^7\times 1.6\times 10^{-19}\\\\q=7.68\times 10^{-12}\ C

So, the net charge is 7.68\times 10^{-12}\ C.

7 0
3 years ago
A first order reaction, A -> products, has a rate reaction of .00250 Ms-1 when [A] = . 484 M. (a) What is the rate constant,
tamaranim1 [39]

Answer: a)  The rate constant, k, for this reaction is 0.00516s^{-1}

b) No t_{\frac{1}{2}} does not depend on concentration.

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

A\rightarrow products

Given: Order with respect to A = 1

Thus rate law is:

a) Rate=k[A]^1

k= rate constant

0.00250=k[0.484]^1

k=0.00516s^{-1}

The rate constant, k, for this reaction is 0.00516s^{-1}

b) Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  

t = age of sample

a = let initial amount of the reactant  

a - x = amount left after decay process  

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{2.303}{k}\log\frac{100}{50}

t_{\frac{1}{2}}=\frac{0.69}{k}

Thus t_{\frac{1}{2}} does not depend on concentration.

8 0
3 years ago
What is the following correct way to write 2,330,000 In a scientific notation
NISA [10]

Answer:

2.33 × 10^6

hope this helps.

8 0
3 years ago
Read 2 more answers
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