Here is your answer:
First find the notations:
2×10^-3
=0002
And...
2.5×10^4=25000
Then divide:
0002÷25000=8E-9
Your answer:
=8 x 10-8
The answer to your question would be C
Answer:
Force exerted by car on truck will be 6000 N in opposite direction
Explanation:
It is given that mass of the car is one quarter of the mass of the truck
Force exerted by the truck on the car is 6000 N
We have to find the force exerted by car on the truck
According to newtons third law for any action there is equal and opposite reaction
So force exerted by car on the truck will be equal to 6000 N in opposite direction
Answer:
See the answers below.
Explanation:
To solve this problem we must use the following equation of kinematics.

where:
Vf = final velocity = 10 [m/s]
Vo = initial velocity = 40 [m/s]
t = time = 5 [s]
a = acceleration [m/s²]
Now replacing:
![10=40-a*5\\40-10=a*5\\30=5*a\\a=6[m/s^{2}]](https://tex.z-dn.net/?f=10%3D40-a%2A5%5C%5C40-10%3Da%2A5%5C%5C30%3D5%2Aa%5C%5Ca%3D6%5Bm%2Fs%5E%7B2%7D%5D)
Note: The negative sign in the above equation means that the velecity is decreasing.
2)
To solve this second part we must use the following equation of kinematics.

where:
x = distance [m]
![(10)^{2} =(40)^{2} -2*6*x\\100=1600-12*x\\12*x=1600-100\\12*x=1500\\x=125[m]](https://tex.z-dn.net/?f=%2810%29%5E%7B2%7D%20%3D%2840%29%5E%7B2%7D%20-2%2A6%2Ax%5C%5C100%3D1600-12%2Ax%5C%5C12%2Ax%3D1600-100%5C%5C12%2Ax%3D1500%5C%5Cx%3D125%5Bm%5D)
Answer:
F=507.7N
Explanation:
According to Newton's second law:

in this case, the football players need to drag the coach at a constant velocity, thus means with no acceleration, so:

there are 20 degrees between the two ropes that means each player exerts a force 10 degrees from the zero reference.
