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3 years ago

Ionic bond two ions what changes

1 answer:

7 0

Ionic bonds <span>are the type of bonds where there is </span>transfer<span> of electrons from one atom to another. The electrons are removed and from one atom and attached to another. A good example is salt which is composed of sodium and chlorine. Sodium readily loses one of its electrons and chlorine readily accepts it. Before losing the electron, sodium has a positive charge, but then becomes negatively charged after giving up the electron. Chlorine has a positive charge before gaining the electron but becomes negatively charged after gaining the electron. These opposite charges between sodium and chlorine attract the two elements together to form the ionic bond.</span>

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A 0.87 kg projectile is fired into the air from the top of a 8.52 m cliff above a valley. Its initial velocity is 9.1 m/s at 49◦

Ann [662]

By adding the time of flight at the top of the cliff and the time taken down the hill, the ball spent 2.72 s of time in air.

<h3>What is a Projectile ?</h3>

A projectile can be a stone or a ball or any object that can be projected. The object projected will take a trajectory path.

Given that acceleration due to gravity is 9.8 m/s and a 0.87 kg projectile is fired into the air from the top of a 8.52 m cliff above a valley. Its initial velocity is 9.1 m/s at 49◦ above the horizontal. To know how long the projectile will be in the air, we will calculate the total time of flight at the top of the cliff and the time taken down the hill

Time of flight T = 2usinФ/g

Where

g = m/s²

Ф = 49°

h = 8.52 m

u = 9.1 m/s

t = ?

m = 0.87 kg

Substitute all the necessary parameters into the formula

T = (2 × 9.1sin49)/ 9.8

T = 13.74/9.8

T = 1.40 s

The time taken down the cliff can be found with formula

h = ut + 1/2gt²

where u = 0

8.52 = 0 + 1/2 × 9.8 × t²

8.52 = 4.9t²

t² = 8.52/4.9

t² = 1.738

t = √1.738

t = 1.32 s

Time for the projectile in the air = T + t

Time in air = 1.40 + 1.32

Time = 2.72 s

Therefore, the projectile will be in the air for 2.72 seconds long.

Learn more about Projectile here: brainly.com/question/24949996

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1 year ago

Question 5

goldfiish [28.3K]

Answer:

Explanation:

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3 years ago

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3 years ago

Cuales son dispositivos de salida?

Jobisdone [24]

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el monitor,las impresoras y las memorias portátiles

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3 years ago

Tarzan, who weighs 825 N, swings from a cliff at the end of a 19.7 m vine that hangs from a high tree limb and initially makes a

kodGreya [7K]

Answer:

a) T = (281.47 i ^ + 714.56 j ^) N , b) F_net = (281.47 i ^ - 110.44 j ^) N ,

c) F = 281.70 N, d) θ = 338.58º , e) a = 3,588 m / s² , f) θ = 201.45º

Explanation:

For this exercise we will use Newton's second law on each axis

X axis

-Tₓ = m aₓ

Y Axisy

$T_{y}$ –W = m a_{y}

Let's use trigonometry to find the components of force

sin 21.5 = Tₓ / T

cos 21.5 = T_{y} / T

Tₓ = T sin 21.5

T_{y} = T cos 21.5

Tₓ = 768 sin 21.5 = 281.47 N

T_{y} = 768 cos 21.5 = 714.56 N

a) the force of the rope on Tarzan is

T = (281.47 i ^ + 714.56 j ^) N

b) The net force is the subtraction of the tension minus the weight of Tarzan

Y Axis F_net = 714.56 - 825 = -110.44 N

F_net = (281.47 i ^ - 110.44 j ^) N

c) Let's use Pythagoras' theorem

F = √ (Fₓ² + T_{y}²)

F = √ (281.47² + 110.44²)

F = 281.70 N

d) Let's use trigonometry

tan θ = F_{y} / Fₓ

θ = tan⁻¹ F_{y} / Fₓ

θ = tan⁻¹ (-110.44 / 281.47)

θ = -21.42º

This angle is average clockwise, for counterclockwise measurement

θ = 360 - 21.42

θ = 338.58º

Acceleration

X axis

Tₓ = m aₓ

aₓ = Tₓ / m

The mass of Tarzan is

m = W / g

m = 825 / 9.8 = 84.18 kg

aₓ = 281.47 / 84.18

aₓ = -3.34 m / s2

Y Axis

T_{y}-W = m a_{y}

a_{y} = (T_{y} -W) / m

a_{y} = (714.56-825) / 84.18

a_{y} = - 1,312 m / s²

Acceleration Module

a = √ aₓ² + a_{y}²

a = √ (3.34² +1.312²)

a = 3,588 m / s²

The angle

θ = tan⁻¹ a_{y} / aₓ

θ = tan⁻¹ (-1312 / -3.34)

θ = 21.45º

Notice that the two components of the acceleration are negative, so the angle is in the third quadrant, to measure from the x-axis

θ = 180 + 21.45

θ = 201.45º

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3 years ago