The electric field is a vector magnitude so when adding we must use vectors, in this case as the initial field E = 4N / c goes towards the axis axis and the field created by the fixed charge (E1) is also on the axis x we can add in scalar form.

E_total = E + E₁

the expression for the field of a point charge is

E₁ = k q₁ / r²

for the point x = 2m, they do not say that the total field is zero, so the charge q1 must be negative

E_total = E -k q₁ / r₂

we substitute

0 = E - k q₁ / r²

q₁ = $\frac{E r^2}{k}$

let's calculate

q₁ = $\frac{4 \ 2^2}{9 \ 10^{-9}}$

q₁ = 1.78 10⁻⁹ C

now we can calculate the field for position x = 4 m

E_total = 4 - 9 10⁹ 1.78 10⁻⁹ / 4²2

E_total = 3 N / A

8 0

3 years ago

Please help me out! Thanks! (:

ElenaW [278]

X=Ft is a possible equation for X because by using SI units its final term became Kg metre per second

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3 years ago

How do electric field lines indicate the strength of the field?

Paha777 [63]

I am almost sure it it (c)

6 0

3 years ago

Read 2 more answers

Points A (-9,2), B (2,-9), and C (-9,-9) are placed in three different quadrants of a Cartesian coordinate system. Convert each

slavikrds [6]

Answer:

answer

Explanation:

5 0

3 years ago