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liq [111]
3 years ago
5

Convert 60 miles per hour into meters per second

Mathematics
1 answer:
Svetllana [295]3 years ago
3 0
1,609.35 meters are in a mile.
3,600 seconds are in an hour.

1,609.35meters x 60miles = 96,561 meters per hour
96,561meters per hour / 3,600seconds = 26.82 meters per second
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51 less than the 8 times an unknown number is equal to 53.
Anton [14]

Let, Unknown number = x

8x-51 = 53

8x = 53+51

x = 104/8

x = 13

8 0
3 years ago
Given that the points (-3, 2) and (1, 2) are vertices of a rectangle, what two sets of coordinates could form the other two vert
polet [3.4K]
-3,2 means on quadrant 4 and 1,2 is in quadrant 1
3 0
3 years ago
The figure below is the graph of the dimensions of a rectangle whose adjacent side lengths exhibit inverse variation.
cricket20 [7]

Answer:

The answer is true just answered

6 0
3 years ago
Read 2 more answers
PLZ HELP, AND PLZ EXPLAIN
shutvik [7]

Answer:

C

Step-by-step explanation:

To make it easy let's start by organizing our information :

  • AC=12 AND BD=8
  • ABCD is a rhombus
  • K and L are the midpoints of sides AD and CD
  • we notice that the rhombus ABCD is divided into four right triangles

What do you think of when you hear a right triangle ?

  • The pythagorian theorem !

AC and BD  are khown so let's focus on them .

If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?

Simply because they are the diagonals of a rhombus .

ow let's apply the pythagorian theorem :

  • (AC/2)² + (BD/2)² = BC²
  • 6²+4²=52
  • BC²= 52⇒\sqrt{52}=BC

Now we khow that : AB=BC=CD=AD=\sqrt{52}

This isn't enough . Let's try to figure out a way to calculate the length of KL  wich is the base of the triangle

  • KL is parallel to AC
  • k is the midpoint of AD and L of DC

I smell something . yes! Thales theorem

  • KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
  • KL/12=\sqrt{52}/2*\sqrt{52}  
  • KL/12=1/2⇒ KL=6

Now we have the length of the base kl

Now the big boss the height :

  • notice that you khow the length of KL
  • BD crosses kl from its midpoint and DL = \sqrt{52} /2

What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D

  • DL²=(KL/2)²+D²
  • 52/4= 9+ D²
  • D² = 52/4-9 +4 SO D=2

now the height of the trigle is H= BD-D= 8-2=6

NOw the area of the triangle is :

  • A=(KL*H)/2 ⇒ A= (6*6)/2=18

THE ANSWER IS 18 SQ.UN

5 0
3 years ago
Anyone know how to do these?
erastovalidia [21]

Answer:

B. 1/m¹⁸

Step-by-step explanation:

To simplify the equation, we start with the values inside the brackets.

Therefore  m⁻¹m⁵ results to m⁴.

This is because the sign between the m⁻¹ and m⁵ is multiplication, and when multiplying figures that have a similar base, we add the indices.

that is, -1+5=4

then we divide m⁴ by m⁻², that is, m⁴/m⁻²=m⁶

To divide figures that have the same base we subtract the powers.

That is, 4-(-2)=6

the resulting expression from inside the brackets will be (m⁶)³ which results to m⁻¹⁸ which is the same as 1/m¹⁸

3 0
3 years ago
Read 2 more answers
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