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AysviL [449]
3 years ago
7

Consider two consecutive positive integers such that the square of the second integer added to 3 times the first is equal to 37.

Mathematics
1 answer:
wlad13 [49]3 years ago
4 0

Am I supposed to consider or solve?   Let's solve.

Let's call our integers x and x+1

square of the second integer added to 3 times the first is 37

(x+1)² + 3x = 37

x² + 2x + 1 + 3x - 37 = 0

x² + 5x - 36 = 0

(x+9)(x-4) = 0

Answer: x = -9 or x=4

Check:

x=-9

(-9+1)² + 3(-9) = 64 - 27 = 37 good

x=4

(4+1)² + 3(4) = 25 + 12 = 37 good

Two solutions.

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To attend the class field trip, 24 students brought their permission slips.
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Answer:

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7 0
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Dale bought a map of his city it uses a scale of 1 inch = 8 miles Dale house and school are 1 1/2 inches apart on the map how fa
shtirl [24]
Alright, if the original scale was 1 inch = 8 miles, and Dale's house to his school are 1 1/2 inches apart, let's find the amount of miles.

Here's a fast way. 1 inch is 8 miles, and half of 8 equals 4 miles, which is 1/2 of an inch., 8 + 4 = 12 miles. 

So if his house and the school were 12 miles apart, and we we're using the 1 inch. = 6 miles scale, then it'd be 2 inches on the map. 

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If 1 inch. = 6 miles
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4 0
3 years ago
What is the simplified form of 15 x to the eighth power over 24 y to the fifth power divided by 4 x to the fourth power over 8 s
IRISSAK [1]
The exponent symbol when typing is ^. so I so rewrite this for you.
(15x^8 / 24y^5) / (4x^4 / 8y^2)

I assumed you meant 8y squared because you said 8 squared.

now when we divide by a fraction, we can actually multiply by it's reciprocal and get the same thing. The word reciprocal really just means flip it over. so:

(15x^8 / 24y^5) * (8y^2 / 4x^4)

let's reduce the coefficients ( the numbers in front of the x and y) to make it easier.

We have 15/24 which can be reduced to 5/8
and 8/4 which is 2/1

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multiply numerator and denominator
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now put together
5x^4 / 4y^3

so C
3 0
3 years ago
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