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lara31 [8.8K]
4 years ago
13

5670 seconds = ? Hours

Mathematics
2 answers:
Leya [2.2K]4 years ago
4 0

Answer:

1.575

Step-by-step explanation:

taurus [48]4 years ago
3 0

Answer:

5670 Seconds

= 1.575 Hours

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A converging lens of focal length 5 cm is placed at a distance of 20
lesya [120]

The object should be placed 20/cm from the lens so as to form its real image on the screen

<h3>Mirror equation</h3>

The mirror equation is given according to the expression below;

1/f = 1/u + 1/v

where

f is the focal length

u is the object distance

v is the image distance

Given the following parameters

f = 5cm

v = 20cm

Required

object distance u

Substitute

1/5 = 1/u +1/20

1/u = 1/5-1/20
1/u = 3/20

u = 20/3 cm

Hence the object should be placed 20/cm from the lens so as to form its real image on the screen

Learn more on mirror equation here; brainly.com/question/27924393

#SPJ1

4 0
2 years ago
F(x)=x2+3x-5 and g(x)=x/4-6.g(x)=x/4-6
xenn [34]

Answer:

idk the answer but i use socratic by google to take pictures of the problems and find answers online, and also cymath.com is a really great place to get answers for math, i hope this helps!

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Calculate area of triangle
Radda [10]

Answer:

60cm^2

Step-by-step explanation:

15 times 8 = 120

divided by 2  = 60

3 0
3 years ago
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4•f(6)-6•g(5)=?<br> i need help ASAP!
adell [148]

Answer:

6

Step-by-step explanation:

f(6) from the graph is -6

g(5) from the graph is -5

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5 0
3 years ago
A statistician selected a random sample of 125 observations from a population with a known standard deviation equal to 16 and co
serious [3.7K]

Answer:

Step-by-step explanation:

Given that a statistician selected a random sample of 125 observations from a population with a known standard deviation equal to 16 and computed a sample mean equal to 77

We can use Z critical values since population std deviation is known. Also sample size >30

We find std error of mean = \frac{16}{\sqrt{125} } \\=1.4311

Margin of error = Z critical value * 1.4311

Z critical values for 93% = 1.81

for 89% = 1.60

n Std error Z critical  Conf interval  

            89%    

     

125 1.4311     1.6  (74.71024 79.28976 )

     

     

          93%    

            1.81  (74.409709 79.590291 )

We find that when confidence level increases interval width increses.

c) When sigma changes to 441, std error changes to \frac{16}{\sqrt{441} } \\=0.7619

So we get

n Std error Z critical  Conf interval  

           89%    

     

441  0.7619     1.6  (75.781 78.219 )

     

     

         93%    

           1.81  (75.621 78.37904)

d) When n = 625, std error changes to 16/25 = 0.64

n Std error Z critical  Conf interval  

        89%    

     

441 0.64 1.6        (75.976 78.024 )

     

     

       93%    

        1.81      (75.842 78.1584)

When sample size increases, confidence interval width decreases.

8 0
3 years ago
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