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trasher [3.6K]
4 years ago
9

Find a glass jar with a screw-top metal lid. Close the lid snugly and put the jar into the refrigerator. Leave it there for abou

t 10 minutes and then take the jar out and try to open the lid. (a) Did the lid become tighter or looser? Explain your observation.
Physics
1 answer:
DochEvi [55]4 years ago
5 0

Answer:

The lid becomes tighter

It becomes tighter because metals have a lower heat capacity than glass meaning their temperature drops (or increases) much faster than glass for the same energy change. So in this example, the metal will contract faster than the glass causing it to be more tighter around the glass.

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How can all matter on Earth be classified?
Dvinal [7]

Answer:

by helping

Explanation:

u see the answer is by helping cause cleaning the earth help and helpingb animals so it would be helping

3 0
3 years ago
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A 0.50-kg ball, attached to the end of a horizontal cord, is rotated in a circle of radius 1.9 m on a frictionless horizontal su
Sedaia [141]

Answer:

\boxed {\boxed {\sf 18 \ m/s}}

Explanation:

The ball is moving in a circle, so the force is centripetal.

One formula for calculating centripetal force is:

F_c= \frac{mv^2}r}

The mass of the ball is 0.5 kilograms. The radius is 1.9 meters. The centripetal force is 85 Newtons or 85 kg*m/s².

  • F_c= 85 kg*m/s²
  • m= 0.5 kg
  • r= 1.9 m

Substitute the values into the formula.

85 \ kg*m/s^2 = \frac{0.5 \ kg *v^2}{1.9 \ m}

Isolate the variable v. First, multiply both sides by 1.9 meters.

(1.9 \ m)(85 \ kg*m/s^2) = \frac{0.5 \ kg *v^2}{1.9 \ m}*1.9 \ m

(1.9 \ m)(85 \ kg*m/s^2) = {0.5 \ kg *v^2}

161.5 \ kg*m^2/s^2 = 0.5 \ kg*v^2

Divide both sides by 0.5 kilograms.

\frac {161.5 \ kg*m^2/s^2}{0.5 \ kg} = \frac{0.5 \ kg*v^2}{0.5 \ kg}

\frac {161.5 \ kg*m^2/s^2}{0.5 \ kg} =v^2

323 \ m^2/s^2 = v^2

Take the square root of both sides of the equation.

\sqrt {323 \ m^2/s^2} =\sqrt{ v^2

\sqrt {323 \ m^2/s^2} =v

17.9722007556 \ m/s =v

The original measurements have 2 significant figures, so our answer must have the same.

For the number we found, 2 sig fig is the ones place. The 9 in the tenth place tells us to round the 7 to an 8.

18 \ m/s =v

The maximum speed is approximately <u>18 meters per second.</u>

8 0
3 years ago
Auniform thin film of n=1.33 is on top of glass (n=1.5). When monochromatic light with tunable wavelength is directed from above
Aleonysh [2.5K]

Answer:

Explanation:

There is reflection ( two times ) from upper and lower surface of the film . In both cases , reflection is from low to  high density medium so there is change in phase of 180 twice .

So for constructive interference

2μd = n λ₁ , d is thickness required , λ is wavelength n₁ is order of  bright fringe

For destructive interference ( minimum light )

2μd = (2n+1) λ₂/2

n λ₁ =(2n+1) λ₂/2

(2n+1) / 2n = λ₁ / λ₂

= 650 / 505

=   5 / 4 ( approx )

2n = 4

n = 2

2μd = n λ₁

2 x 1.33 x d = 2 x 650 nm

d = 488.72 nm

5 0
3 years ago
An athlete can twirl a baton so that it reaches an angular velocity of 12 rad/s from rest in 0.5 s. If the length of a uniform b
NikAS [45]

Answer:

The torque needed is 46.08 Nm

Explanation:

Given;

angular velocity, ω = 12 rad/s

time of motion, t = 0.5 s

length of the baton, r = 0.8 m

mass of the baton, 0.5 kg

The torque needed to  reach the angular velocity is given by;

τ = F x r

where;

F is the centripetal force of the baton

r is the length of the baton = radius of the circular motion of the baton

F_c =ma_c= \frac{mv^2}{r} = m\omega^2 r

Torque is given by;

\tau = F_c *r\\\\\tau = m \omega^2 r *r\\\\\tau = m \omega^2 r^2 \\\\\tau = (0.5)(12)^2(0.8)^2\\\\\tau = 46.08 \ N m

Therefore, the torque needed is 46.08 Nm

6 0
3 years ago
In the speed-time graph for a moving object shown here, the part which
Nikitich [7]

Answer:

I think the answer is ST. Option B

4 0
3 years ago
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