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Travka [436]
2 years ago
6

1. is the full moon a spring tide or neap tide

Physics
2 answers:
denpristay [2]2 years ago
7 0
The greatest tidal extremes occur when the Sun, Moon, and Earth
are all lined up along the same straight line.  Those occasions are
at the time of the Full Moon ... when the Earth is the middle one ...
and the time of the New Moon ... when the Moon is the middle one. 
Those are the occasions of the highest high tides and the lowest
low tides, known collectively as "Spring tides".

The smallest tidal extremes occur when the Sun, Moon, and Earth
form a right angle, with the Earth at the vertex.  Those occasions are
at the time of the First Quarter and Third Quarter Moon.  Those are
the occasions of the highest low tides and the lowest high tides,
known collectively as "Neap tides".


#1 & #3:  Spring tides
#2:  False
kkurt [141]2 years ago
5 0
Question 1: the full moon is a spring tide

Question 2 is true. Neap Tides do have higher and lower tides than normal.

Question 3: (the same as Question 1)-- The new moon is a spring tide
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If you have to pick 3 answers then B, C, and D but if you pick only 1 answer then pick D
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Which of these is the easiest mineral identification property to use when you want to know whether you have pyrite or actual gol
Makovka662 [10]

Answer:

c. streak

Explanation:

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2 years ago
A missile is moving 1350 m/s at a 25.0° angle. It needs to hit a target 23,500 m away in a 55.0° direction in 10.20 s. What is d
QveST [7]

Answer:

  The target's velocity is about 1320 m/s in the direction 265.7°.

Explanation:

In order for there to be a collision between missile and target, we must have ...

  (target starting position) + (target movement) = (missile movement)

assuming the missile starts from the origin of all measurements. The missile moves 10.2 seconds before impact, so moves a distance of ...

  (10.2 s)(1350 m/s) = 13,770 m

__

We are interested in the target movement, so we can solve for that:

  (target movement) = (missile movement) - (target starting position)

In terms of meters, this is ...

  (target movement) = 13770∠25° - 23500∠55° ≈ 13467.74∠-94.3°

The target covers this distance in the same 10.2 seconds before collision, so its speed is (13467.74 m)/(10.2 s) ≈ 1320.4 m/s.

As a positive angle, the target's direction is ...

  -94.3° +360° = 265.7°

The direction of the target's velocity is 265.7°.

_____

If you're calculating this by hand, there are a couple of ways you can do it. You can convert to rectangular coordinates and back (perhaps least confusing), or you can use the law of cosines to solve the triangle, then translate angles back to the x-y coordinate plane.

Using rectangular coordinates, we have ...

  13770∠25° = 13770(cos(25°), sin(25°)) ≈ (12479.9, 5819.45)

  23500∠55° = 23500(cos(55°), sin(55°)) ≈ (13479.0, 19250.1)

Then the difference is ...

  (12479.9, 5819.45) -(13479.0, 19250.1) ≈ (-999.188, -13430.6)

and the (3rd-quadrant) angle is ...

  target direction = arctan(-13430.6/-999.188) ≈ -94.3° = 265.7°

__

The target's speed is found by dividing the distance it covers by the time it takes.

  √(13430.6² +999.188²)/10.2 ≈ 1320.36 . . . m/s

3 0
3 years ago
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Answer:

2560J

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By definition the kinetic energy can be calculated in the following way:

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7 0
2 years ago
The pressure of air pushing down on a house roof is extremely large. Why is the roof not crushed?
Degger [83]
There is still air inside of a house, which is pushing the roof upwards, so the forces are equal and the roof is not crushed.
7 0
3 years ago
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