Answer:
3.83×10¯⁴ N
Explanation:
From the question given above, the following data were obtained:
Charge 1 (q₁) = +2.4x10¯⁸ C
Charge 2 (q₂) = +1.8x10¯⁶ C
Distance apart (r) = 1.008 m
Electrical constant (K) = 9×10⁹ Nm²/C²
Force (F) =?
The magnitude of the electrical force acting between the two charges can be obtained as follow:
F = Kq₁q₂ / r²
F = 9×10⁹ × 2.4x10¯⁸ × 1.8x10¯⁶ / (1.008)²
F = 0.0003888 / 1.016064
F = 3.83×10¯⁴ N
Thus the magnitude of the electrical force acting between the two charges is 3.83×10¯⁴ N
Answer:
a = 2.84 m/s²
Explanation:
Given that,
Net force, F = 2500 N
Mass of the car, m = 880 kg
We need to find the acceleration of the car. Net force is given by :
F = ma

So, the acceleration of the car is 2.84 m/s².
Answer:
60/90
Explanation:
I think because the train's highest velocity is 60 n the time is 90
That is 164.592cm = 5.4 feet