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3 years ago

I will give brainliest! The prime factors of a number are 2,2,2, and 5. What is the number?

Mathematics

1 answer:

BartSMP [9]3 years ago

6 0

Answer:

Step-by-step explanation:

The number with those factors is ...

2×2×2×5 = 40

_____

You can give Brainliest with only one answer when the opportunity is presented. Time must pass.

You might be interested in

Y = -3x - 2 and 5x + 2y = 15

denis-greek [22]

Answer:

(-19, 55)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Algebra I

Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

y = -3x - 2

5x + 2y = 15

Step 2: Solve for x

Substitution

Substitute in y: 5x + 2(-3x - 2) = 15
Distribute 2: 5x - 6x - 4 = 15
Combine like terms: -x - 4 = 15
Isolate x term: -x = 19
Isolate x: x = -19

Step 3: Solve for y

Define original equation: y = -3x - 2
Substitute in x: y = -3(-19) - 2
Multiply: y = 57 - 2
Subtract: y = 55

8 0

3 years ago

Let f(x)=x^2+x+2 and g(x)=2x^2+5. find f(g(x)). Show each step of your work. Please help me!

hodyreva [135]

Just let every x in f(x) be g(x)
it means:
f(g(x))=(2x^2+5)^2+(2x^2+5)+2
=4x^4+20x^2+25+2x^2+5+2
=4x^4+22x^2+32

5 0

3 years ago

Suppose you have pennies, nickels, and dimes in your pocket. If you pull out four coins, what possible amount of money could you

mina [271]

Well first we need to know how many pennies, nickles, and dimes there are.

3 0

3 years ago

Read 2 more answers

Factorize this fully 20x² +500x+3000

Serga [27]

Answer:

20(x+15)(x+10)

Step-by-step explanation:

Hi there!

As your question states, we need to fully factor the polynomial: 20x²+500x+3000

These are pretty big numbers; let's pull out the GCF, as that will make it easier to factor

the GCF is 20

so factoring 20 out of the polynomial will get:

20(x²+25x+150)

As you can see, the polynomial inside the parenthesis is a lot easier to factor than the original with really big numbers.

Now use FOIL to factor x²+25x+150 into 2 binomials

25 is the sum of the last terms

150 is the product of the last terms

think: which two numbers add up to 25 but multiply to get 150?

those two numbers are 15 and 10

x²+25x+150 factored is (x+15)(x+10)

but remember we have the 20 in front of x²+25x+150 (or now, (x+15)(x+10))

therefore the fully factored binomial is 20(x+15)(x+10)

Hope this helps! :)

5 0

3 years ago

A certain bowler can bowl a strike 85 % of the time. What is the probability that she a) goes three consecutive frames without

Artist 52 [7]

Answer:

a) 0.34% probability that she goes three consecutive frames without a strike.

b) 1.91% probability that she her first strike in the third frame

c) 99.66% probability that she has at least one strike in the first three frames.

d) 14.22% probability that she bowls a perfect game.

Step-by-step explanation:

For each frame, there are only two possible outcomes. Either there is a strike, or there is not. The probability of a strike happening in a frame is independent of other frames. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A certain bowler can bowl a strike 85 % of the time.

This means that $p = 0.85$

a) goes three consecutive frames without a strike?

This is $P(X = 0)$ when $n = 3$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{3,0}.(0.85)^{0}.(0.15)^{3} = 0.0034$

0.34% probability that she goes three consecutive frames without a strike.

b) makes her first strike in the third frame?

No strike during the first two(with a 15% probability)

Strike during the third(85% probability). So

P = 0.15*0.15*0.85 = 0.0191

1.91% probability that she her first strike in the third frame

c) has at least one strike in the first three frames? 

Either there are no strikes, or there is at least one strike. The sum of the probabilities of these events is 100%.

From a), 0.34% probability that she goes three consecutive frames without a strike.

100 - 0.34 = 99.66

99.66% probability that she has at least one strike in the first three frames.

d) bowls a perfect game (12 consecutive strikes)?

This is $P(X = 12)$ when $n = 12$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 12) = C_{12,12}.(0.85)^{12}.(0.15)^{0} = 0.1422$

14.22% probability that she bowls a perfect game.

3 0

4 years ago