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GrogVix [38]
3 years ago
7

What is the first step in solving the following equation: −1\2x − 33 = 33

Mathematics
2 answers:
lesya692 [45]3 years ago
8 0

Answer:

add 33 to both sides

Step-by-step explanation:

Given

- \frac{1}{2} x - 33 = 33 ( add 33 to both sides )

- \frac{1}{2} x = 66 ( multiply both sides by - 2 to clear the fraction )

x = - 132

satela [25.4K]3 years ago
7 0

Answer:

First step is to make x the subject of the equation.

Step-by-step explanation:

-\frac{1}{2} x - 33 = 33\\\\-\frac{1}{2} x= 33 + 33\\\\-\frac{1}{2} x = 66\\\\- x = 2 \times 66 = 132\\x = -132

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MakcuM [25]

Answer:

a. x

b. 35

c. 45

d. y

Explanation:

a. The independent variable is not dictated by any other variable. x is the only variable here that fits that description is x.

b. A coefficient is a constant that multiplies any variable. 35 multiplies x, so it is a coefficient.

c. A constant is a number that cannot change and isn't a coefficient. 45 cannot be changed.

d. The dependent variable is dictated by other variables. y is dictated by x, so it is the dependent variable.

7 0
4 years ago
Read 2 more answers
M2 = 10x + 2 and m2) = 9x + 8.<br> Find x.<br> U<br> Solve for x.
Finger [1]

Answer:

x=m2/10 − 1/5

x=m2/9 − 8/9

Step-by-step explanation:

4 0
4 years ago
Given: m∠AEB = 45°
Oksanka [162]

Answer:

Answer is B. angle addition postulate

Step-by-step explanation:

-UvU-

3 0
3 years ago
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Three fifths of the baker's 60 cookies were chocolate chip. How many of the cookies were chocolate chip?
zheka24 [161]

Answer:

24 cookies

Step-by-step explanation:

5 0
4 years ago
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First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x
e-lub [12.9K]

Answer:

(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

\int x ln(5+x)dx

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

\int (U-5) ln(U)dU

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

\int (pq')=pq-\int qp'

so we must define p, q, p' and q':

p=ln U

p'=\frac{1}{U}dU

q=\frac{U^{2}}{2}-5U

q'=U-5

and now we plug these into the formula:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU

Which simplifies to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU

Which solves to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C

so we can substitute U back, so we get:

\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C

and now we can simplify:

\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

notice how all the constants were combined into one big constant C.

7 0
4 years ago
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