1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mezya [45]
3 years ago
6

If the price of a cd that normally costs $17.50 was marked up by 8% what is the new cost

Mathematics
1 answer:
Nana76 [90]3 years ago
3 0
CD cost=17.50
Marked up=8%
So 8%of 17.50
8÷100×17.50=1.4
So add the old cd cost to the answer
=17.50+1.4=18.9 is the new cost
You might be interested in
-6x + 5y = 1<br> 6x + 4y = –10
Firlakuza [10]

Answer:

x=-1

y=-1

Step-by-step explanation:

-6x + 5y =1 ......equation (1)

6x + 4y = –10 ......equation (2)

adding equation (1) to equation (2)

9y=-9

9y/9 =-9/9 (dividing both side by the coefficient of y)

y=-1

subtituting the value of y =-1 into equation (2)

6x+4(-1)=-10

6x+(-4)=-10

6x-4=-10

6x=-10+4(making constant to be at one side and the variable at the other side)

6x=-6

x=-6/6

x=-1

8 0
3 years ago
I just need help with 6c. If you can, please explain how you got the answer.​
vagabundo [1.1K]

she could do multiplication AND division

3 0
3 years ago
Select two prime numbers that have a sum of 18.
AURORKA [14]

Step-by-step explanation:

option e.5,13

.............

6 0
3 years ago
There is a bag with only red marbles and blue marbles. The probability of randomly choosing a red marble is 2 9 . There are 63 m
Tatiana [17]

The main idea is the number of marbles and the denominator of the probability. All you have to do is multiply the fraction by a fraction which is equal to 1 which makes the denominator equal to 63. We know 63 is a multiple of 9. 9 goes 7 times in 63 so we multiple the fraction \frac{2}{9} with \frac{7}{7} which gives, \frac{2 * 7}{9 * 7} which when evaluated gives \frac{14}{63} and the numerator is the number of red marbles in the bag. So there are 14 red marbles in the bag :D

7 0
3 years ago
If two lines are parallel which statement must be true? A.Their slopes are zero. B.Their slopes are negative reciprocals. C. The
stepan [7]

Answer:

D

Step-by-step explanation:

Parallel lines have the same gradient.

A line with a slope of zero is a horizontal line. Although two lines that have a slope of zero will result in two parallel lines, not all parallel lines are horizontal lines. Since the question is asking for which statement <u>must</u> be true, option A is incorrect.

If the slopes of two lines are negative reciprocals, they are perpendicular to each other. This is because the product of the gradients of 2 perpendicular lines is -1. Let the gradient of the first line be A and the other be B.

AB= -1

A =   - \frac{ 1}{B}

B =  -  \frac{1}{A}

Thus, option B is incorrect too.

Undefined slopes gives vertical lines. Like option A, if two lines have an undefined slope, they will be parallel to each other. However since parallel lines are nit necessarily vertical lines, option C is also incorrect.

4 0
3 years ago
Read 2 more answers
Other questions:
  • What is the image point of (1,8) after a translation left 2 units and down 1 unit
    14·1 answer
  • Please help me with some Algebra 2!
    10·1 answer
  • Add -3 5/6 + 5 3/7<br><br> A.) 1 25/42<br> B.) 2 8/13<br> C.)-9 11/42<br> D.) 1 27/42
    10·1 answer
  • Anticent math problem how many rabbitsand phesants 35 heads and 94 feet
    13·1 answer
  • Assuming an initial bracket of [1, 5] for bisection method, the first (at the end of 1 iteration) iterative value of the root of
    11·1 answer
  • Can you help me I am stuck on it​
    5·1 answer
  • Which coin will touch the bottom first?25°c and 25°f​
    5·1 answer
  • Find y (-3,y) and (1,-7) m=-4
    9·1 answer
  • Find the equation of the exponential function represented by the table below
    13·1 answer
  • The raidius of the circle is r=___The equation of the circle in standard form____
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!