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kow [346]
3 years ago
15

A parallelogram is shown below:

Mathematics
2 answers:
shepuryov [24]3 years ago
4 0

Answer:

AREA

Step-by-step explanation:

area of parallelogram equal to BD into 8 feet into 3 by 4 6 feet

the area of the triangle ADB equal to the area of triangle DBC be equal to 3

Ket [755]3 years ago
3 0

Part A

9x8/9=72/9=8 square feet

Part B

Draw a line diagonally either between point A&C or B&D, this would make 2 triangles

The area of the triangle would be half of the full area so 8/2= 4 feet square

Could you put me as brainliest?

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Answer:

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Step-by-step explanation:

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Follow the steps to finish solving the equation -3x+18=7x
Svet_ta [14]

Answer:

x = 1.8

Step-by-step explanation:

We have the equation -3x + 18 = 7x. First we do your step 1, and get: 18 = 10x. When doing your step 2, we divide both sides by 10 to isolate x alone. 18/10 = 1.8. X = 1.8

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3 years ago
Which of the following represents the equation of the line passing through (-4,5)
Sergio [31]

Answer:

Answer: y=2x+13.

Step-by-step explanation:

Your input: find the equation of the line perpendicular to the line y=5/2−x/2 passing through the point (−4,5).

The equation of the line in the slope-intercept form is y=5/2−x/2.

The slope of the perpendicular line is negative inverse: m=2.

So, the equation of the perpendicular line is y=2x+a.

To find a, we use the fact that the line should pass through the given point: 5=(2)⋅(−4)+a.

Thus, a=13.

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5 0
4 years ago
Please help meeh thank u thank u
Sunny_sXe [5.5K]

Answer:

The location would be between 4 and 5.

Step-by-step explanation:

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5 0
3 years ago
Resolve into partial fractions<br><br>​
lisabon 2012 [21]

Answer:

See below

Step-by-step explanation:

1)

\frac{11 + x}{(2 - x)(x - 3)}  =  \frac{A}{2 - x}  +  \frac{B}{x - 3}  \\  \\  \therefore \:  \frac{11 + x}{(2 - x)(x - 3)}  =  \frac{A(x - 3) +B(2 - x) }{(2 - x)(x - 3)}   \\  \\ \therefore \:  11 + x = Ax - 3A + 2B - Bx \\  \\  \therefore \: 11 + x = - 3A  + 2B  + Ax -  Bx\\  \\  \therefore \: 11 + x = - 3A  + 2B  + (A - B)x \\  \\ equating \: the \: like \: terms \: on \: both \: sides \\ A - B = 1 \\  \therefore \: A  =  B  +  1.....(1) \\  \\  -  3A  + 2B = 11....(2) \\  from \: eq \: (1) \: and \: (2) \\  - 3(B  +  1) + + 2B = 11 \\  \\ - 3B   - 3  + 2B = 11 \\  \\  - B = 11 + 3 \\  \\ B =  - 14  \\ A  =   - 14 +  1 =  - 13 \\  \\  \frac{11 + x}{(2 - x)(x - 3)}  =  \frac{ - 13}{2 - x}  +  \frac{ - 14}{x - 3} \\  \\ \frac{11 + x}{(2 - x)(x - 3)}  = -   \frac{ 13}{2 - x}   -  \frac{ 14}{x - 3}

2)

\frac{12x + 11}{x^2 +x - 6}

=\frac{12x + 11}{x^2 +3x-2x - 6}

=\frac{12x + 11}{x(x +3) -2(x +3)}

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{12x + 11}{(x +3) (x - 2)}

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{A}{(x +3)}+\frac{B}{(x - 2)}

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{A(x-2)+B(x+3)}{(x-2)(x+3)}

\therefore 12x + 11 = A(x-2)+B(x+3)

\therefore 12x + 11 = Ax-2A+Bx+3B

\therefore 12x + 11 = Ax+Bx-2A+3B

\therefore 12x + 11 = (A+B) x-2A+3B

Equating like terms on both sides:

A + B = 12\implies A = 12-B... (1)

- 2A + 3B = 11... (2)

Solving equations (1) & (2), we find:

A = 5, B = 7

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{5}{(x +3)}+\frac{7}{(x - 2)}

3 0
3 years ago
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