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2 years ago

A parallelogram is shown below:

Mathematics

2 answers:

shepuryov [24]2 years ago

4 0

Answer:

AREA

Step-by-step explanation:

area of parallelogram equal to BD into 8 feet into 3 by 4 6 feet

the area of the triangle ADB equal to the area of triangle DBC be equal to 3

Ket [755]2 years ago

3 0

Part A

9x8/9=72/9=8 square feet

Part B

Draw a line diagonally either between point A&C or B&D, this would make 2 triangles

The area of the triangle would be half of the full area so 8/2= 4 feet square

Could you put me as brainliest?

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The school water fountain can only fill 3/4 of a jug at a time. With this amount of water, Mr. Kern can water 3/8 of his plants.

Vesnalui [34]

Answer:

$\frac{3}{4} = \frac{3}{3} \\ \frac{3}{8} = x \\ x = \frac{3}{8} \times \frac{4}{3} \\ x = \frac{1}{2}$

5 0

2 years ago

Find the solution of:

iogann1982 [59]

6 / (x+1) = 1/2
x +1 = 12
x = 11
Answer is d ....(11)

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3 years ago

How state the roots as points when I have <br> x=6 and x=-2

dem82 [27]

I don't really know what you're trying to ask because

x = -2 and x=6 are your roots.

But if you want to convert them back to their equation form,

get the other side of the equation to be 0.

x = 6

x - 6 = 0

x = -2

x + 2 = 0

so your original equation had something like (x+2)(x-6)

6 0

3 years ago

Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m

GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

$d=\sqrt{\frac{3h}{2} }$

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

$d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)$

For Addison h=85(1/3)

$d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)$

Subtracting both distances we get

$8\sqrt{2}-6\sqrt{2} =2\sqrt{2}$

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0

2 years ago

Please help me, no links or random answers, please. When you are writing the answer please number it so I know which answer is f

meriva

Answer

A: (1,7.5)

b:(0,6)

c: because the graph is linear graph and have a constant rate of change/ slope which is -1.5

Step-by-step explanation:

5 0

2 years ago