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3 years ago

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In the next olympics the united states can enter four athletes in the divivng competition. how many different teams of four dive

rs can be selected from a group of nine divers?

1 answer:

n200080 [17]3 years ago

4 0

If you have 9 divers total and each team can only have 4 divers, then logically the US can select 2 teams of 4 from 9 divers.

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Given the equation p = s Subscript 1 Baseline t minus 2 Subscript 2 Baseline t, which equation is solved for t? t = p (s Subscri

gulaghasi [49]

Answer:

Option C) is correct

That is t=StartFraction p Over s Subscript 1 Baseline minus s Subscript 2 Baseline EndFraction

It also can be written as $t=\frac{p}{s_{1}-s_{2}}$

Step-by-step explanation:

Given equation can be written as below:

$p=s_{1}t-s_{2}t$

Now to solve the equation for t:

$p=s_{1}t-s_{2}t$

Taking common term t outside on RHS we get

$p=(s_{1}-s_{2})t$

$\frac{p}{s_{1}-s_{2}}=t$

Rewritting the above equation as below

$t=\frac{p}{s_{1}-s_{2}}$

Therefore option C) is correct

That is t=StartFraction p Over s Subscript 1 Baseline minus s Subscript 2 Baseline EndFraction

It also can be written as $t=\frac{p}{s_{1}-s_{2}}$

5 0

2 years ago

Read 2 more answers

When asked to factor the trinomial x^2-16x+64, a student gives the answer (x – 8)(x + 8). Which of the following statements is t

Murrr4er [49]

Answer:

The answer is incorrect; the plus sign should be a minus sign (apex)

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

In which of the following units is acceleration expressed? A. Newtons B. Kilograms C. Foot-pounds D. Meters per second squared

ELEN [110]

Answer:

D. Meters per second

Step-by-step explanation:

here's why the answer is D even though they arent the best explanations but none the less the answer is still right.

1. Newton = force

2.kilo = mass

3. foot-pound = force

4. Meters Per sec = speed/acceleration

3 0

3 years ago

3.2 geometry worksheet

alekssr [168]

Answer/Step-by-step explanation:

5. 21x + 4 = 22x - 2 (corresponding angles)

Collect like terms

21x - 22x = -4 - 2

-x = -6

divide both sides by -1

x = 6

6. (x + 72) + (x + 132) = 180 (linear pair)

x + 72 + x + 132 = 180

Add like terms

2x + 204 = 180

2x = 180 - 204

2x = -24

x = -12

7. 90 = 22x + 2 (vertical angles)

90 - 2 = 22x

88 = 22x

Divide both sides by 22

4 = x

x = 4

8. 12x + 10 = 13x + 3 (vertical angles)

Collect like terms

12x - 13x = -10 + 3

-x = -7

Divide both sides by -1

x = 7

9. 17x = 16x + 5 (alternate exterior angles)

17x - 16x = 5

x = 5

✔️17x

Plug in the value of x

17(5) = 85°

10. 21x - 6 = 20x (corresponding angles)

Add like terms

21x - 20x = 6

x = 6

✔️20x

20(6) = 120°

3 0

3 years ago

Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be

hodyreva [135]

Answer:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

And the sample deviation with the following formula:

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

And the sample deviation with the following formula:

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

8 0

3 years ago